If a gas occupies 2.40 L at a pressure of 4.4 atmospheres, what will its volume be at 8.8 atmospheres? a 5.2 L b 19.4 L c 1.2 L d 4.8 L
We can use Boyle's Law to solve this problem, which states that the pressure and volume of a gas are inversely proportional at constant temperature.
According to Boyle's Law:
Pressure1 * Volume1 = Pressure2 * Volume2
Let's plug in the values we have:
4.4 atm * 2.40 L = 8.8 atm * Volume2
Now, we can solve for Volume2:
2.40 L = (4.4 atm * 2.40 L) / 8.8 atm
2.40 L = 1.20 L
Therefore, the volume of the gas at 8.8 atmospheres will be 1.2 L.
So the answer is c) 1.2 L
To solve this problem, we can use Boyle's Law, which states that the volume of a gas is inversely proportional to its pressure when temperature is constant.
Boyle's Law can be represented by the equation:
P₁V₁ = P₂V₂
where P₁ and V₁ are the initial pressure and volume, and P₂ and V₂ are the final pressure and volume.
Given:
P₁ = 4.4 atm
V₁ = 2.40 L
P₂ = 8.8 atm
Let's substitute these values into the equation and solve for V₂:
4.4 atm * 2.40 L = 8.8 atm * V₂
10.56 L = 8.8 atm * V₂
Now, divide both sides of the equation by 8.8 atm:
(10.56 L) / (8.8 atm) = V₂
V₂ ≈ 1.2 L
Therefore, the volume will be approximately 1.2 L at a pressure of 8.8 atmospheres. So the correct answer is c) 1.2 L.
To solve this problem, we can use Boyle's Law, which states that the pressure of a gas is inversely proportional to its volume when temperature is held constant. Mathematically, it can be represented as:
P1 * V1 = P2 * V2
Where:
P1 = Initial pressure
V1 = Initial volume
P2 = Final pressure (unknown)
V2 = Final volume (unknown)
Let's plug in the given values into the equation and solve for V2:
P1 = 4.4 atm
V1 = 2.40 L
P2 = 8.8 atm
V2 = ?
4.4 atm * 2.40 L = 8.8 atm * V2
10.56 L atm = 8.8 atm * V2
Now, divide both sides of the equation by 8.8 atm to solve for V2:
V2 = 10.56 L atm / 8.8 atm
V2 ≈ 1.20 L
Therefore, the volume of the gas at 8.8 atmospheres will be approximately 1.20 L.
So, the correct answer is option c) 1.2 L.