A volume of gas at 2.50 atm was measured at 3.70 L. What will be the volume if the pressure is adjusted to 1.90 atm?
Use the sample problem below and follow the 5 steps to help you solve the problem you were given.
a
4.87 L
b
1.28 L
c
17.75 L
d
2.81 L
To solve this problem, we can use Boyle's Law, which states that the volume of a gas is inversely proportional to the pressure of the gas.
Step 1: Write down the known information:
Initial pressure (P1) = 2.50 atm
Initial volume (V1) = 3.70 L
Final pressure (P2) = 1.90 atm
Step 2: Write down the formula for Boyle's Law:
P1 * V1 = P2 * V2
Step 3: Plug in the known values into the formula:
(2.50 atm) * (3.70 L) = (1.90 atm) * V2
Step 4: Solve for the unknown variable (V2):
V2 = (2.50 atm * 3.70 L) / 1.90 atm
Step 5: Calculate the answer:
V2 ≈ 4.87 L
Therefore, the volume will be approximately 4.87 L if the pressure is adjusted to 1.90 atm.
To solve the problem, we can use Boyle's law, which states that the pressure and volume of a gas are inversely proportional when temperature is kept constant.
Step 1: Write down the given information:
Initial pressure (P1) = 2.50 atm
Initial volume (V1) = 3.70 L
Final pressure (P2) = 1.90 atm
Step 2: Set up the equation using Boyle's law:
P1 * V1 = P2 * V2
Step 3: Substitute the given values into the equation:
(2.50 atm) * (3.70 L) = (1.90 atm) * (V2)
Step 4: Solve for V2:
V2 = (2.50 atm * 3.70 L) / 1.90 atm
V2 = 4.87 L
Step 5: Answer the question:
The volume will be 4.87 L if the pressure is adjusted to 1.90 atm.
Therefore, the correct answer is option (a) 4.87 L.
To solve this problem, we can use Boyle's Law, which states that the pressure and volume of a gas are inversely proportional when the temperature is constant. Boyle's Law is expressed as P1V1 = P2V2, where P1 and V1 are the initial pressure and volume, and P2 and V2 are the final pressure and volume.
In this case, we are given P1 = 2.50 atm, V1 = 3.70 L, and P2 = 1.90 atm. We need to find V2.
To find V2, we can rearrange Boyle's Law equation to solve for V2:
V2 = (P1 * V1) / P2
Now, let's substitute the given values into the equation:
V2 = (2.50 atm * 3.70 L) / 1.90 atm
To calculate this, we multiply the initial pressure (2.50 atm) by the initial volume (3.70 L), and then divide the result by the final pressure (1.90 atm).
V2 = (9.25 L * atm) / 1.90 atm
The units "atm" cancel out, leaving us with:
V2 = 9.25 L / 1.90
Now, we divide 9.25 L by 1.90 to find the final volume:
V2 = 4.87 L
Therefore, the volume will be 4.87 L when the pressure is adjusted to 1.90 atm. Therefore, the correct answer is option a.