A student wanted to investigate changing the mass of a cart that you can push. The student pushed both carts with a force of 200 Newtons. If one cart has a mass of 100kg and the other cart a mass of 50kg, what results would the student expect to see as far as how fast each cart moved in comparison with one another?
Type Answer HERE:
The student would expect to see that the cart with a mass of 50kg will move faster than the cart with a mass of 100kg.
To compare the speed at which each cart moves, we need to apply Newton's second law of motion, which states that force is equal to mass multiplied by acceleration (F = ma).
Given that the student pushes both carts with a force of 200 Newtons, we can calculate the acceleration of each cart using the formula:
Acceleration = Force / Mass
For the cart with a mass of 100kg:
Acceleration = 200 N / 100 kg = 2 m/s^2
For the cart with a mass of 50kg:
Acceleration = 200 N / 50 kg = 4 m/s^2
Therefore, the student would expect to see the cart with a mass of 50kg moving faster than the cart with a mass of 100kg.
To determine how fast each cart would move in comparison with one another, we can use Newton's second law of motion, which states that the acceleration of an object is directly proportional to the net force exerted on it and inversely proportional to its mass.
The formula to calculate acceleration is:
acceleration = net force / mass
Given that the student pushes both carts with a force of 200 Newtons, we can calculate the acceleration for each cart using the mass values provided.
For the cart with a mass of 100 kg:
acceleration = 200 N / 100 kg = 2 m/s²
For the cart with a mass of 50 kg:
acceleration = 200 N / 50 kg = 4 m/s²
Therefore, the student would expect to see that the cart with a mass of 50 kg would move faster than the cart with a mass of 100 kg.
A scientist wanted to move a golf ball and a bowling ball to both reach 15 mph. What would the scientist have to do differently for the bowling ball than the golf ball to reach his goal?
Type Answer HERE:
To make both the golf ball and the bowling ball reach 15 mph, the scientist would have to apply different amounts of force to each ball.
According to Newton's second law of motion, the acceleration of an object is directly proportional to the net force applied to it and inversely proportional to its mass. To achieve the same acceleration for both balls, the scientist would need to apply a greater net force to the bowling ball compared to the golf ball.
This is because the bowling ball has a greater mass than the golf ball. The scientist would have to exert a larger force on the bowling ball to overcome its greater mass and achieve the same acceleration as the golf ball.
In summary, the scientist would have to apply a greater force to the bowling ball compared to the golf ball to make both reach 15 mph.
Each time the man stopped and took a break, what happened to the line on the Position-Time Graph (Blue Graph). Explain why.
Type Answer HERE:
Each time the man stopped and took a break, the line on the Position-Time graph (Blue Graph) would become flat or horizontal, indicating that the man's position did not change over time.
This is because during the break, the man's motion stopped, and he remained at the same position. In terms of the Position-Time graph, when an object is not moving, the line representing its position becomes a horizontal line, indicating a constant position.
So, each time the man stopped and took a break, the line on the Position-Time graph (Blue Graph) would become flat to represent the lack of change in the man's position during that time.
Each time the man stopped and took a break, what happened to the line on the Velocity-Time Graph (Red Graph). Explain why.
Type Answer HERE:
Each time the man stopped and took a break, the line on the Velocity-Time graph (Red Graph) would become a horizontal line at zero velocity or flat.
This is because when the man stops and takes a break, his velocity becomes zero. Velocity is defined as the rate at which an object changes its position in a given direction. When the man stops, he is no longer changing his position, and hence, his velocity becomes zero. The flat line on the Velocity-Time graph represents this zero velocity during the period of the break.
So, each time the man stops and takes a break, the line on the Velocity-Time graph (Red Graph) would become a horizontal line at zero velocity to represent the absence of motion during that time.