For what value of a will 8x10^3 be larger than ax10^2?
To find the value of a where 8x10^3 is larger than ax10^2, we need to compare the coefficients of the powers of 10.
The coefficient of 8x10^3 is 8.
The coefficient of ax10^2 is a.
To ensure that 8x10^3 is larger than ax10^2, the coefficient 8 needs to be greater than the coefficient a. Therefore, a < 8.
To determine the value of "a" for which 8x10^3 is larger than ax10^2, we need to compare the numerical values (ignoring the powers of 10).
8x10^3 can be simplified to 8000.
Similarly, ax10^2 can be simplified to (a * 100).
So, we want to find the value of "a" for which 8000 is greater than (a * 100).
Mathematically, this can be written as:
8000 > a * 100
To solve for "a," we can divide both sides of the inequality by 100:
8000 / 100 > a
80 > a
Therefore, "a" needs to be less than 80 for 8x10^3 to be larger than ax10^2.
To find the value of "a" for which 8x10^3 is larger than ax10^2, we can set up an inequality and solve it.
First, let's compare the powers of 10. We know that 10^3 is larger than 10^2, so we can ignore the powers of 10 for now and focus on the coefficients.
Comparing 8 and "a," we need 8 to be larger than "a" for 8x10^3 to be larger than ax10^2.
Therefore, we can write the inequality:
8 > a
Now we can solve for "a" by isolating it:
a < 8
This means that any value of "a" less than 8 will make 8x10^3 larger than ax10^2.