Edet took sixth at the end of term tests and each test was marked out of 80. If his marks were 48, 52, 46, 46, 44 and 52. What percentage of the total marks did he get?
To find the total marks for all the tests, you need to add up all the individual marks: 48 + 52 + 46 + 46 + 44 + 52 = 288
He received a score of 288 out of a possible 480 points because 6 x 80 = <<6*80=480>>480
To find the percentage received, you divide his score by the total possible score and multiply by 100: (288 / 480) x 100 = 60%. Answer: \boxed{60}.
To calculate the percentage of the total marks that Edet got, we first need to find the total number of marks he received.
To find the total mark, we sum up all the individual marks:
48 + 52 + 46 + 46 + 44 + 52 = 288
Now that we have the total marks received, we can calculate the percentage:
Percentage = (Total Marks Obtained / Total Marks) * 100
In this case:
Percentage = (288 / (80 * 6)) * 100
To calculate this, first find the total possible marks:
Total Marks = 80 * 6 = 480
Now substitute the values back into the equation:
Percentage = (288 / 480) * 100
Simplifying the equation gives:
Percentage = 0.6 * 100
Therefore, Edet received 60% of the total marks.
To find the percentage of total marks Edet got, we need to calculate the sum of his marks and then divide it by the total possible marks, and finally multiply by 100 to get the percentage.
First, let's find the sum of his marks:
48 + 52 + 46 + 46 + 44 + 52 = 288
The total possible marks for all the tests:
80 + 80 + 80 + 80 + 80 + 80 = 480
Now, let's calculate the percentage:
(288 / 480) * 100 = 60
Therefore, Edet got 60% of the total marks.