Last week, Malika’s cat slept 18 hours each day. Her baby slept 91 hours total for the week. Compare the proportional relationship of the number of hours the cat and baby sleep each day.(1 point)
Responses
Both the cat and the baby spend less than half the hours of the day sleeping.
Both the cat and the baby spend less than half the hours of the day sleeping.
The cat slept fewer hours per day than the baby.
The cat slept fewer hours per day than the baby.
The baby slept fewer hours per day than the cat.
The baby slept fewer hours per day than the cat.
The cat and the baby slept the same amount of hours total for the week.
The baby slept fewer hours per day than the cat.
To compare the proportional relationship of the number of hours the cat and baby sleep each day, we need to calculate the average number of hours per day for each.
The cat slept 18 hours each day for the week. To find the average number of hours per day, we divide the total hours (18) by the number of days in a week (7): 18 / 7 = 2.57 hours per day (rounded to the nearest hundredth).
The baby slept 91 hours total for the week. Again, to find the average number of hours per day, we divide the total hours (91) by the number of days in a week (7): 91 / 7 = 13 hours per day (rounded to the nearest whole number).
Comparing the averages, we can see that the baby slept more hours per day than the cat, as 13 is greater than 2.57. Therefore, the correct answer is: The baby slept fewer hours per day than the cat.
To compare the proportional relationship of the number of hours the cat and baby sleep each day, we need to divide the total number of hours they slept by the number of days in the week.
The cat slept 18 hours each day for 7 days, which is a total of 18 x 7 = 126 hours.
The baby slept 91 hours total for the week.
Since there are 7 days in a week, we can find the average number of hours slept per day by dividing the total number of hours slept by the number of days.
For the cat: 126 hours / 7 days = 18 hours per day.
For the baby: 91 hours / 7 days = 13 hours per day.
Comparing the average hours slept per day, we can conclude that the cat slept fewer hours per day than the baby.
Use the tables to answer the question.
Company A
Hours of Work Pay ($)
5.5 140.25
22.0 561.00
35.0 892.50
40.0 1,020.00
Company B
Hours of Work Pay ($)
4.0 114.00
10.6 302.10
20.5 584.25
35.0 997.50
Based on the tables showing what two leading gas brands pay employees, compare which company pays the higher rate. Which answer provides the correct company and hourly rate?
(1 point)
Responses
Company A has the best hourly rate of $1,020/40 hours.
Company A has the best hourly rate of $1,020/40 hours.
Company B has the best hourly rate of $28.50/hour.
Company B has the best hourly rate of $28.50/hour.
Company B has the best hourly rate of $997.50/40 hours.
Company B has the best hourly rate of $997.50/40 hours.
Company A has the best hourly rate of $25.50/hour.
Company A has the best hourly rate of $25.50/hour.
Skip to navigation
page 13 of 13
To determine which company pays the higher rate, we need to divide the pay by the number of hours worked for each job.
For Company A, we divide the pay for 40 hours of work ($1,020) by the number of hours (40): $1,020 / 40 = $25.50/hour.
For Company B, we divide the pay for 35 hours of work ($997.50) by the number of hours (35): $997.50 / 35 = $28.50/hour.
Comparing the hourly rates, we can conclude that Company B has the higher rate of $28.50/hour. Therefore, the correct answer is: Company B has the best hourly rate of $28.50/hour.
Use the tables to answer the question.
Marco’s Homework
Number of Days Number of Hours
3 3.25
9 9.75
12 13.0
30 32.5
Maribella’s Homework
Number of Days Number of Hours
4 4.2
8 8.4
20 21.0
28 29.4
Based on the tables showing the hours of homework done by Marco and Maribella for different periods of time, which statement is correct?
(1 point)
Responses
Marco spends less time on homework per night.
Marco spends less time on homework per night.
Marco and Maribella spend equal time doing their homework.
Marco and Maribella spend equal time doing their homework.
There is not enough information to tell who spends less time doing their homework.
There is not enough information to tell who spends less time doing their homework.
Maribella spends less time on homework per night.
Maribella spends less time on homework per night.
Skip to navigation
page 13 of 13
To determine who spends less time on homework per night, we need to calculate the average number of hours per day for each student.
For Marco, we divide the total number of hours (32.5) by the total number of days (30): 32.5 / 30 = 1.08 hours per day (rounded to the nearest hundredth).
For Maribella, we divide the total number of hours (29.4) by the total number of days (28): 29.4 / 28 = 1.05 hours per day (rounded to the nearest hundredth).
Comparing the averages, we can see that Maribella spends slightly less time on homework per night than Marco, as 1.05 is slightly less than 1.08. Therefore, the correct answer is: Maribella spends less time on homework per night.
Use the tables to answer the question.
Community A
Number of Households Total Number of Children
10 26
20 52
40 104
75 195
Community B
Number of Households Total Number of Children
12 30
24 60
50 125
85 212.5
Based on the tables showing the average number of children per household for two different communities, which community has the most children if both neighborhoods have the same number of households? How many children live in this community if 1,000 households?
(1 point)
Responses
Community B has the most children. There are 2,500 children in this community if there are 1,000 households.
Community B has the most children. There are 2,500 children in this community if there are 1,000 households.
Community B has the most children. There are 212.5 children which is greater than the 195 in Community A.
Community B has the most children. There are 212.5 children which is greater than the 195 in Community A.
Community A has the most children. There are 2,600 children in this community if there are 1,000 households.
Community A has the most children. There are 2,600 children in this community if there are 1,000 households.
Community A has the most children. There are 260 children in this community if there are 1,000 households.
Community A has the most children. There are 260 children in this community if there are 1,000 households.
Skip to navigation
page 13 of 13
To determine which community has the most children if both neighborhoods have the same number of households, we need to compare the average number of children per household.
For Community A, we divide the total number of children (195) by the total number of households (75): 195 / 75 = 2.6 children per household.
For Community B, we divide the total number of children (212.5) by the total number of households (85): 212.5 / 85 = 2.5 children per household.
Comparing the average number of children per household, we can see that Community A has a slightly higher average of 2.6 children per household, while Community B has an average of 2.5 children per household. Therefore, the correct answer is: Community A has the most children if both neighborhoods have the same number of households.
To determine the number of children in Community A if there are 1,000 households, we multiply the average number of children per household (2.6) by the number of households (1,000): 2.6 x 1,000 = 2,600 children.
Therefore, there would be 2,600 children in Community A if there are 1,000 households.