solve the following quadratic equation by factoring
x^2+3x=18
please type your answers from least to gratest for ex x1 be smallest and x2 be the greatest
show all the steps
To solve the equation x^2 + 3x = 18 by factoring:
Step 1: Move all terms to one side of the equation to set it equal to zero:
x^2 + 3x - 18 = 0
Step 2: Factor the quadratic expression on the left side of the equation:
(x + 6)(x - 3) = 0
Step 3: Set each factor equal to zero and solve for x:
x + 6 = 0 -> x = -6
x - 3 = 0 -> x = 3
Therefore, the solutions to the quadratic equation x^2 + 3x = 18 are:
x1 = -6
x2 = 3
To solve the quadratic equation x^2 + 3x = 18 by factoring, follow these steps:
Step 1: Write the equation in standard form: x^2 + 3x - 18 = 0.
Step 2: Factor the quadratic expression on the left side of the equation. Look for two numbers that multiply to give -18 and add up to 3. In this case, the numbers are 6 and -3. So, the factored form of the equation becomes: (x + 6)(x - 3) = 0.
Step 3: Set each factor equal to zero and solve for x. So, we have:
x + 6 = 0 or x - 3 = 0.
Step 4: Solve for x in each equation:
For x + 6 = 0: Subtract 6 from both sides:
x = -6.
For x - 3 = 0: Add 3 to both sides:
x = 3.
So, the solutions to the quadratic equation are x = -6 and x = 3.
Therefore, x1 = -6 and x2 = 3.
To solve the quadratic equation x^2 + 3x = 18 by factoring, we first rearrange the equation to bring all terms to one side:
x^2 + 3x - 18 = 0
Next, we look for two numbers that multiply to give -18 (the coefficient of x^2 * the constant term) and add up to 3 (the coefficient of x). In this case, the numbers are 6 and -3:
(x + 6)(x - 3) = 0
By applying the zero product property, we set each factor equal to zero and solve for x:
x + 6 = 0 -> x = -6
x - 3 = 0 -> x = 3
Therefore, the solutions to the quadratic equation x^2 + 3x = 18 are x = -6 and x = 3, where x1 = -6 (the smallest) and x2 = 3 (the greatest).