Two weeks before an examination day, a librarian monitored the number of students who visited the library. Then they compared it with the number of visits made in an average week. Approximately 2 x 10^3 visits were reflected in their logbook during this two-week period, While only about 5 x 10^2 were reflected on an average week. How many times higher is the number of library visits before examination day compared to the libary visits in an average week? Your answer should be a whole number.

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To find the number of times higher the number of library visits before examination day is compared to the visits in an average week, we need to divide the number of visits before examination day by the number of visits in an average week.

Number of visits before examination day = 2 x 10^3
Number of visits in an average week = 5 x 10^2

Number of times higher = (2 x 10^3) / (5 x 10^2) = (2/5) x (10^3/10^2) = 0.4 x 10 = 4

Therefore, the number of library visits before examination day is 4 times higher than the visits in an average week.

To find out how many times higher the number of library visits before the examination day is compared to an average week, we need to calculate the ratio between the two.

First, let's determine the number of visits in an average week: 5 x 10^2 (≡ 500).

Then, we calculate the number of visits before the examination day: 2 x 10^3 (≡ 2000).

To calculate the ratio, we divide the number of visits before the examination day by the number of visits in an average week:

2000 / 500 = 4.

Therefore, the number of library visits before the examination day is 4 times higher than the number of visits in an average week.

To find out how many times higher the number of library visits before the examination day is compared to an average week, we need to divide the number of visits before the examination day by the number of visits in an average week.

The number of visits before the examination day is approximately 2 x 10^3, and the number of visits in an average week is about 5 x 10^2.

So, the calculation would be:
(2 x 10^3) / (5 x 10^2)

To simplify the division, we can divide the numerator and the denominator by 10^2 to cancel out the common factor.

(2 x 10^3) / (5 x 10^2) = (2/5) x (10^3/10^2)

Simplifying the fractions gives us:
(2/5) x 10^(3-2) = (2/5) x 10^1 = 2 x 10^1

Finally, 2 x 10^1 equals 20.

Therefore, the number of library visits before the examination day is 20 times higher than the number of visits in an average week.