Amaris soccer team will play 15 games this season. That is 7 games fewer than 2 times the number of games they played last season. How many games did they play last season? Which equation represents this problem?
Let's represent the number of games played last season as "x".
The number of games they will play this season is 2x - 7.
The equation representing this problem is 2x - 7 = 15.
Let's represent the number of games they played last season as "x".
According to the problem, Amaris soccer team will play 7 games fewer than 2 times the number of games they played last season.
So, 2x - 7 = 15 represents this problem.
To find the number of games Amaris soccer team played last season, we can use algebraic expressions and equations.
We are given that Amaris' team will play 15 games this season. Let's represent the number of games played last season with the variable "x".
According to the given information, "15" is 7 games fewer than 2 times the number of games they played last season. In other words, 15 is equal to 2 times the number of games played last season minus 7.
So, we can write the equation as:
15 = 2x - 7
To find the number of games played last season, we need to solve this equation for x.
To do that, we can first add 7 to both sides of the equation:
15 + 7 = 2x
22 = 2x
Next, divide both sides of the equation by 2 to isolate x:
22/2 = x
11 = x
Therefore, the number of games Amaris' soccer team played last season is 11.
The equation that represents this problem is:
15 = 2x - 7