Solve the equation. Note if the equation is an identity or if it has no solution.
-2(-c-20)=-2c-20
Select the correct choice and fill in any answer boxes in your choice below.
A. c=
B.The equation is an identity.
C.The equation has no solution.
To solve the equation, we can start by simplifying both sides:
-2(-c-20)=-2c-20
Distribute -2 on the left side:
2c+40=-2c-20
Now, let's add 2c to both sides:
2c+2c+40=-2c+2c-20
4c+40=-20
Next, subtract 40 from both sides:
4c+40-40=-20-40
4c=-60
Now, divide both sides by 4:
(4c)/4=(-60)/4
c=-15
Therefore, the solution to the equation is c=-15. The correct choice is A. c=-15.
To solve the equation -2(-c-20)=-2c-20, we can simplify both sides of the equation.
On the left side, we apply the distributive property: -2(-c-20) = 2c + 40.
On the right side, -2c-20 remains the same.
So, the equation becomes:
2c + 40 = -2c - 20.
Now, we can combine like terms by subtracting 2c from both sides:
2c - 2c + 40 = -2c - 2c - 20.
This simplifies to:
40 = -4c - 20.
Next, we can add 20 to both sides of the equation:
40 + 20 = -4c - 20 + 20.
This becomes:
60 = -4c.
To solve for c, we divide both sides of the equation by -4:
c = 60 / -4.
Simplifying further, c = -15.
Therefore, the correct choice is A. c = -15.
To solve the equation -2(-c-20)=-2c-20, let's simplify each side step by step:
First, distribute -2 to the terms inside the parentheses on the left side:
-2*(-c-20) = -2*c - 2*(-20)
2c + 40 = -2c - 20
Next, combine like terms on each side:
2c + 40 = -2c - 20
To isolate the variable c, let's move all terms with c to one side and all constants to the other side:
Add 2c to both sides:
2c + 2c + 40 = -2c + 2c - 20
4c + 40 = -20
Subtract 40 from both sides:
4c + 40 - 40 = -20 - 40
4c = -60
Divide both sides by 4 to solve for c:
(4c)/4 = (-60)/4
c = -15
So the solution to the equation is c = -15.
Therefore, the correct choice is:
A. c = -15