In the following equation, how many atoms of oxygen are in the products?
C2H8 + 4 O2 → 2 CO2 + 4 H2O
In the products of the equation, there are 4 atoms of oxygen in the 2 CO2 and another 8 atoms of oxygen in the 4 H2O.
Therefore, there are a total of 4 + 8 = 12 atoms of oxygen in the products.
In the balanced chemical equation you provided:
C2H8 + 4 O2 → 2 CO2 + 4 H2O
To determine the number of oxygen atoms in the products, we need to look at the coefficients in front of each molecule or compound.
In the products, we have:
2 CO2
4 H2O
Since each CO2 molecule contains one carbon atom and two oxygen atoms, the total number of oxygen atoms from CO2 is 2 × 2 = 4.
Since each H2O molecule contains two hydrogen atoms and one oxygen atom, the total number of oxygen atoms from H2O is 4 × 1 = 4.
Adding the oxygen atoms contributed by CO2 and H2O, the total number of oxygen atoms in the products is 4 + 4 = 8.
Therefore, there are 8 oxygen atoms in the products.
To determine the number of atoms of oxygen in the products, we need to examine the coefficients in the balanced equation.
In the given equation:
C2H8 + 4 O2 → 2 CO2 + 4 H2O
We can see that on the reactant side, there are 4 molecules of O2. However, on the product side, there are 2 molecules of CO2 and 4 molecules of H2O. Since each CO2 molecule contains 2 oxygen atoms and each H2O molecule contains 1 oxygen atom, we need to calculate the total number of oxygen atoms in the products.
For CO2: 2 CO2 x 2 oxygen atoms = 4 oxygen atoms
For H2O: 4 H2O x 1 oxygen atom = 4 oxygen atoms
Therefore, the total number of oxygen atoms in the products is 4 + 4 = 8.