Balance the following equation:

Cl2 (g) +AlI3(aq)->I2(aq)+AlcI(aq)

a
2, 1, 3. 1
b
2, 3, 3, 2
c
3, 2, 3, 2
d
1, 1, 1, 1

c) 3, 2, 3, 2

To balance the equation:

Cl2 (g) + AlI3(aq) -> I2(aq) + AlCl3(aq)

we need to ensure that the number of each type of atom is the same on both sides of the equation.

The number of chlorine (Cl) atoms on both sides is already balanced.

The number of aluminum (Al) atoms on both sides is already balanced.

The number of iodine (I) atoms on the left side is 3 (from AlI3), but on the right side, it is 2 (from I2). Therefore, we need to balance the iodine atoms.

To balance the iodine atoms, we can change the coefficient of AlI3 to 2:

Cl2 (g) + 2 AlI3(aq) -> I2(aq) + AlCl3(aq)

Now the number of iodine (I) atoms on both sides is 4.

The balanced equation is:

Cl2 (g) + 2 AlI3(aq) -> I2(aq) + AlCl3(aq)

So, the correct answer is option: c) 3, 2, 3, 2.

To balance the equation, we need to make sure that the number of each type of element is the same on both sides of the equation. Here's how you can balance the given equation:

First, let's start by balancing the chlorine (Cl) atoms. Currently, we have 2 chlorine atoms on the left side and only 1 on the right side. To balance this, we can place a coefficient of 2 in front of AlCl3 on the right side:

Cl2 (g) + AlI3(aq) -> I2(aq) + 2 AlCl3(aq)

Now, the chlorine atoms are balanced, but the iodine (I) atoms are not. We have 1 iodine atom on the left and 2 on the right. To balance this, we can place a coefficient of 2 in front of I2 on the left side:

Cl2 (g) + AlI3(aq) -> 2 I2(aq) + 2 AlCl3(aq)

Now, the iodine atoms are balanced, but the aluminum (Al) atoms are not. We have 1 aluminum atom on the left and 2 on the right. To balance this, we can place a coefficient of 2 in front of AlI3 on the left side:

Cl2 (g) + 2 AlI3(aq) -> 2 I2(aq) + 2 AlCl3(aq)

Now, the aluminum atoms are balanced as well as all the other atoms in the equation.

The balanced equation is:
Cl2 (g) + 2 AlI3(aq) -> 2 I2(aq) + 2 AlCl3(aq)

So, the correct answer would be option c: 3, 2, 3, 2.