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Karen measured her height as 59 inches. That is 27 inches more than half her older sister's height. How tall is her older sister? (1 point)

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To solve this problem, we need to set up an equation.

Let x be the height of Karen's older sister.
We know that Karen's height is 59 inches, which is 27 inches more than half her older sister's height.
Therefore, we can write the equation: x/2 + 27 = 59.
To solve for x, we need to isolate x on one side of the equation.
Subtracting 27 from both sides gives us: x/2 = 59 - 27.
Simplifying, x/2 = 32.
To solve for x, we multiply both sides of the equation by 2: x = 64.
Therefore, Karen's older sister is 64 inches tall.

To find out how tall Karen's older sister is, we need to use the given information. We know that Karen's height is 59 inches, which is 27 inches more than half her older sister's height.

Let's call Karen's older sister's height "x".

According to the information, 59 inches is 27 inches more than half of her older sister's height.

To express this mathematically, we can write the following equation:

59 = (1/2)x + 27

To solve this equation, we can first subtract 27 from both sides to isolate the term (1/2)x:

59 - 27 = (1/2)x

Simplifying, we have:

32 = (1/2)x

To find x, we can multiply both sides of the equation by 2:

2 * 32 = 2 * (1/2)x

64 = x

Therefore, Karen's older sister's height is 64 inches.

To find out how tall Karen's older sister is, we need to solve the given equation.

Let's assume Karen's older sister's height is 'x' inches. According to the problem, Karen's height is 59 inches, which is 27 inches more than half her older sister's height.

Half of her sister's height is x/2 inches, and 27 inches more than that is (x/2) + 27 inches.

So, we can set up the equation:

(x/2) + 27 = 59

To solve this equation, we need to isolate 'x' on one side. First, we subtract 27 from both sides:

(x/2) = 59 - 27
(x/2) = 32

To get rid of the fraction, we multiply both sides by 2:

2 * (x/2) = 2 * 32
x = 64

Therefore, Karen's older sister's height is 64 inches.