If N is the set of natural numbers that are factors of 45, list the set in roster form.
N = {1, 3, 5, 9, 15, 45}
To list the set N in roster form, we need to find all the natural numbers that are factors of 45.
The prime factorization of 45 is 3 x 3 x 5.
Using this information, we can list the factors of 45 as:
N = {1, 3, 5, 9, 15, 45}
Therefore, the set N in roster form is {1, 3, 5, 9, 15, 45}.
To list the set of natural numbers that are factors of 45 in roster form, we need to determine all the numbers that divide evenly into 45.
To find the factors of a number, we can start by dividing the number by 1 and then continue dividing by successive natural numbers, checking if the division is exact.
For 45, we can divide it by 1:
45 ÷ 1 = 45
The division is exact, so 1 is a factor of 45.
Next, we divide 45 by 2:
45 ÷ 2 = 22.5
Since the division is not exact, 2 is not a factor of 45.
We continue this process until we reach the square root of 45, which is approximately 6.71.
Continuing the division, we find that the factors of 45 are 1, 3, 5, 9, 15, and 45.
Therefore, the set of natural numbers that are factors of 45, listed in roster form, is N = {1, 3, 5, 9, 15, 45}.