Use the unbalanced chemical equation to answer the question. 2NaHCO3 --> Na2CO3+CO2
which of the following can be added to the products to balance the equation. H2O, CH2OH, H2, O2
To balance the given unbalanced chemical equation, you need to have an equal number of atoms on both sides of the equation. Let's start by counting the atoms on each side:
On the left-hand side (reactants):
- 2 sodium (Na) atoms
- 2 hydrogen (H) atoms
- 2 carbon (C) atoms
- 6 oxygen (O) atoms
On the right-hand side (products):
- 2 sodium (Na) atoms
- 1 carbon (C) atom
- 3 oxygen (O) atoms
To balance the equation, the number of atoms for each element on both sides should be equal. In this case, you need to balance the carbon and oxygen atoms.
Since the carbon (C) is underbalanced (2 on the left side vs. 1 on the right side), you would need to add a coefficient of 2 in front of Na2CO3 to balance the carbon atoms. The equation becomes:
2NaHCO3 -> 2Na2CO3 + CO2
Now let's look at the oxygen (O) atoms. On the left-hand side, you have 2 from NaHCO3 and none from CO2. On the right-hand side, you have 6 from Na2CO3 and 1 from CO2. Since the number of oxygen atoms is already balanced, you do not need to add any additional substances to balance the equation in terms of oxygen.
Therefore, from the options given, you would not need to add H2O, CH2OH, H2, or O2 to the products to balance the equation.
To balance the chemical equation, we need to make sure that the number of atoms for each element is equal on both sides.
Looking at the unbalanced equation: 2NaHCO3 -> Na2CO3 + CO2
- We have 2 sodium (Na) atoms on the left and 2 on the right, so sodium is already balanced.
- We have 2 hydrogen (H) atoms on the left and 0 on the right, so hydrogen is not balanced.
- We have 2 carbon (C) atoms on the right, but none on the left, so carbon is not balanced.
- We have 6 oxygen (O) atoms on the right (3 from Na2CO3 and 3 from CO2), but only 6 (2 from NaHCO3) on the left, so oxygen is not balanced.
To balance the equation, we need to add a coefficient in front of the molecules. Adding coefficients changes the number of molecules or formula units, but does not change the identity of the substance.
- To balance hydrogen (H), we need to add 2 H2O molecules on the left side, which will give us 4 hydrogen atoms.
2NaHCO3 + 2H2O -> Na2CO3 + CO2
- To balance carbon (C), we need to add a coefficient of 2 in front of Na2CO3 on the right side, which will give us 2 carbon atoms.
2NaHCO3 + 2H2O -> 2Na2CO3 + CO2
- To balance oxygen (O), we need to add a coefficient of 3/2 (or 1.5) in front of CO2 on the right side, which will give us 9/2 (or 4.5) oxygen atoms.
2NaHCO3 + 2H2O -> 2Na2CO3 + 3/2 CO2
In conclusion, the substance that can be added to the products to balance the equation is O2.
To balance the given unbalanced chemical equation 2NaHCO3 -> Na2CO3 + CO2, we need to examine the number of atoms on each side of the equation.
On the left side of the equation, we have:
- 2 sodium (Na) atoms
- 2 hydrogen (H) atoms
- 2 carbon (C) atoms
- 6 oxygen (O) atoms
On the right side of the equation, we have:
- 2 sodium (Na) atoms
- 1 carbon (C) atom
- 3 oxygen (O) atoms
- 1 carbon dioxide (CO2) molecule
To balance the equation, we need to adjust the number of atoms on both sides. Since we have an imbalance in the number of carbon atoms, we can add CO2 to the products to balance it. The correct option is therefore CO2.