Find the x and y intercepts of the following linear equation.
8x-9y=144
To find the x-intercept, we set y to zero and solve for x.
8x - 9(0) = 144
8x = 144
x = 18
So the x-intercept is 18.
To find the y-intercept, we set x to zero and solve for y.
8(0) - 9y = 144
-9y = 144
y = -16
So the y-intercept is -16.
Therefore, the x-intercept is 18 and the y-intercept is -16.
To find the x-intercept, we need to set y = 0 and solve for x. Similarly, to find the y-intercept, we need to set x = 0 and solve for y.
To find the x-intercept:
1. Set y = 0 in the given equation: 8x - 9(0) = 144.
2. Simplify the equation: 8x = 144.
3. Divide both sides of the equation by 8: x = 144/8.
4. Calculate the value of x: x = 18.
Therefore, the x-intercept is (18,0).
To find the y-intercept:
1. Set x = 0 in the given equation: 8(0) - 9y = 144.
2. Simplify the equation: -9y = 144.
3. Divide both sides of the equation by -9: y = 144/-9.
4. Calculate the value of y: y = -16.
Therefore, the y-intercept is (0,-16).
In summary, the x-intercept is (18,0) and the y-intercept is (0,-16).
To find the x-intercept of a linear equation, we need to set y = 0 and solve for x.
Let's set y = 0 in the equation 8x - 9y = 144:
8x - 9(0) = 144
8x = 144
x = 144/8
x = 18
So, the x-intercept is at the point (18,0).
To find the y-intercept of a linear equation, we need to set x = 0 and solve for y.
Let's set x = 0 in the equation 8x - 9y = 144:
8(0) - 9y = 144
-9y = 144
y = 144/-9
y = -16
So, the y-intercept is at the point (0, -16).