steve and michelle neely are celebrating their 30th anniversary by having a reception at a local reception hall. They have budgeted $4,500 for their reception. If the reception hall charges a $80 cleanup fee plus $30 per person, find the greatest number of people that they may invite and still stay within their budget.
Let's denote the number of people they can invite as "x".
The total cost of the reception hall is given by the equation:
80 + 30x = 4500.
To find the greatest number of people they can invite and still stay within their budget, we need to solve for x in the equation above.
Subtracting 80 from both sides of the equation:
30x = 4500 - 80,
30x = 4420.
Dividing both sides by 30:
x = 4420/30,
x ≈ 147.33.
Since it is not possible to invite a fraction of a person, the greatest whole number of people they can invite is 147.
Therefore, they can invite a maximum of 147 guests and still stay within their budget.
To find the greatest number of people Steve and Michelle may invite and still stay within their budget, we need to consider the maximum amount they can spend on the reception.
The maximum amount they can spend is their budget minus the cleaning fee.
Budget = $4,500
Cleaning fee = $80
Maximum spending on food and drinks = $4,500 - $80 = $4,420
Now, let's calculate how many guests they can invite based on the remaining budget.
Cost per guest = $30
Maximum number of guests = Maximum spending / Cost per guest
Maximum number of guests = $4,420 / $30
Maximum number of guests ≈ 147 guests
Therefore, Steve and Michelle can invite a maximum of 147 guests and still stay within their budget.
To find the greatest number of people that Steve and Michelle may invite while staying within their budget, we need to consider the reception hall charges and the total cost.
First, let's calculate the total cost:
The cleanup fee is $80.
The cost per person is $30.
Let the number of people they invite be represented by 'x'.
So, the cost of inviting 'x' people is given by the equation:
Total Cost = Cleanup Fee + (Cost per Person * Number of People)
Total Cost = $80 + ($30 * x)
Since the total cost cannot exceed their budget of $4,500, we can set up an inequality:
$80 + ($30 * x) ≤ $4,500
Now, let's solve this inequality for 'x':
$30 * x ≤ $4,500 - $80
$30 * x ≤ $4,420
x ≤ $4,420 / $30
x ≤ 147.33
Since the number of people must be a whole number, the maximum number of people they may invite is 147.
So, the greatest number of people they may invite while staying within their budget is 147.