Write an equation of the line in standard form with integer coefficients.
y=1/3x-5
To convert the equation y=1/3x-5 into standard form with integer coefficients, we first multiply every term by 3 to eliminate the fraction:
3y = 3(1/3x-5)
3y = x - 15
Next, we move the x term to the left side of the equation:
-x + 3y = -15
Rearranging the terms in descending order of powers:
-x + 3y = -15
Since this equation is now in standard form with integer coefficients, it meets the requirement.
To write the equation of the line in standard form with integer coefficients, we need to eliminate the fraction.
Given:
y = (1/3)x - 5
To eliminate the fraction, let's clear the fraction by multiplying everything by 3:
3y = 3 * (1/3)x - 5 * 3
Simplifying further:
3y = x - 15
Since the standard form of a linear equation is Ax + By = C, we need to rewrite the equation in this form.
Rearranging the equation, we get:
x - 3y = 15
Therefore, the equation of the line in standard form with integer coefficients is x - 3y = 15.
To write the equation of the line in standard form with integer coefficients, we need to eliminate any fractions or decimals and express the equation in the form Ax + By = C, where A, B, and C are integers.
Given the equation: y = (1/3)x - 5
To eliminate the fraction, we can multiply both sides of the equation by 3 to get rid of the denominator:
3y = 1x - 15
Next, let's rearrange the equation, so the x-term is positive and the coefficients are integers:
x - 3y = 15
Now the equation is in standard form with integer coefficients.