NH3+AgNO3+H2O——>AgOH+NH4NO3
Calculate the concentration of ammonia needed in 1.0 L of solution to fully react 3.0 × 10^-3 mol of silver nitrate.
Based on the balanced chemical equation:
NH3 + AgNO3 + H2O → AgOH + NH4NO3
We can see that the ratio of NH3 to AgNO3 is 1:1. This means that to fully react 3.0 × 10^-3 mol of AgNO3, we would need 3.0 × 10^-3 mol of NH3.
To find the concentration of NH3, we need to know the volume of the solution in which the reaction occurs. Let's assume it is 1.0 L.
Concentration (M) = Number of moles / Volume (L)
Concentration of NH3 = (3.0 × 10^-3 mol) / (1.0 L) = 3.0 × 10^-3 M
Therefore, the concentration of NH3 needed in 1.0 L of solution to fully react 3.0 × 10^-3 mol of silver nitrate is 3.0 × 10^-3 M.
To calculate the concentration of ammonia needed to react with silver nitrate, we need to determine the stoichiometry of the reaction.
The balanced equation for the reaction is:
NH3 + AgNO3 + H2O → AgOH + NH4NO3
From the balanced equation, we can see that the mole ratio between NH3 and AgNO3 is 1:1. This means that 1 mole of NH3 will react with 1 mole of AgNO3.
Given that 3.0 × 10^-3 mol of AgNO3 will fully react, we know that we need the same amount of NH3. Therefore, we need 3.0 × 10^-3 mol of NH3.
Now, we can calculate the concentration of NH3 (in mol/L) in the 1.0 L solution by dividing the moles of NH3 by the volume (in liters):
Concentration of NH3 = (moles of NH3) / (volume of solution)
Concentration of NH3 = (3.0 × 10^-3 mol) / (1.0 L)
Concentration of NH3 = 3.0 × 10^-3 mol/L
To calculate the concentration of ammonia needed, we need to use stoichiometry and the balanced chemical equation:
NH3 + AgNO3 + H2O -> AgOH + NH4NO3
From the equation, we can see that the molar ratio between NH3 and AgNO3 is 1:1. This means that one mole of NH3 reacts with one mole of AgNO3.
Given that we have 3.0 × 10^-3 mol of AgNO3, we can conclude that we need an equal number of moles of NH3 to fully react with it.
Therefore, the concentration of NH3 needed in 1.0 L of solution can be calculated as follows:
Concentration (M) = Number of Moles / Volume (L)
Substituting the values:
Concentration (M) = 3.0 × 10^-3 mol / 1.0 L
Concentration (M) = 3.0 × 10^-3 M
Hence, the concentration of ammonia needed in 1.0 L of solution to fully react 3.0 × 10^-3 mol of silver nitrate is 3.0 × 10^-3 M.