How many atoms of carbon (C) are present in the reactants of the following chemical equation? C7H16+O2→CO2+H2O
There are 7 atoms of carbon (C) present in the reactant C7H16.
To determine the number of carbon atoms present in the reactants, we need to examine the formula of each reactant in the chemical equation.
In the given equation, the reactants are C7H16 and O2. Let's start with C7H16.
The subscript 7 in C7H16 implies that there are 7 carbon atoms present in each molecule of C7H16.
Therefore, in one molecule of C7H16, there are 7 carbon atoms.
However, we need to consider how many molecules of C7H16 are involved in the reaction. Since the coefficient of C7H16 is 1, it indicates that there is only one molecule of C7H16.
Thus, in the reactant C7H16, there are a total of 1 × 7 = 7 carbon atoms.
Therefore, in the reactants of the given chemical equation, there are 7 carbon atoms.
To find the number of atoms of carbon (C) present in the reactants of the given chemical equation, we need to first count the number of carbon atoms in each molecule involved in the reaction.
In this equation, we have two molecules containing carbon:
1. C7H16: This molecule is called heptane and contains 7 carbon atoms (as indicated by the subscript 7 in the chemical formula).
2. CO2: This molecule is carbon dioxide and contains 1 carbon atom.
To find the total number of carbon atoms in the reactants, we add up the number of carbon atoms in each molecule:
Number of carbon atoms in heptane (C7H16) = 7
Number of carbon atoms in carbon dioxide (CO2) = 1
Adding these two values together, we get:
7 + 1 = 8
Therefore, there are 8 atoms of carbon (C) present in the reactants of the given chemical equation.