Use the table to answer the question. (x+3)(x+4)=0 x−3=0 x+4=0 x=3 x=−4 While using the Zero Product Property to find the values of x that make the quadratic equation (x+3)(x+4) equals 0, Oliver completed the work provided in the table. Is Oliver’s work accurate?(1 point) Responses Yes, the work is accurate. Yes, the work is accurate. No, he should have a third column where he should set x=0. No, he should have a third column where he should set x equals 0 . No, x−3=0 in the second row should be x+3=0. No, x minus 3 equals 0 in the second row should be x plus 3 equals 0 . No, x+4=0 in the second row should be x−4=0.
No, x−3=0 in the second row should be x+3=0.
No, x−3=0 in the second row should be x+3=0. No, x minus 3 equals 0 in the second row should be x plus 3 equals 0. No, x+4=0 in the second row should be x−4=0.
Oliver's work is partially accurate, but there are some errors in the table.
To determine the values of x that make the quadratic equation (x+3)(x+4) equals 0 true, we can use the Zero Product Property, which states that if the product of two factors is equal to zero, then at least one of the factors must be equal to zero.
Looking at Oliver's work, we see that he correctly factored the quadratic equation as (x+3)(x+4) = 0. This step is accurate.
However, in the table, there are some errors. The second row should be x+3=0 instead of x−3=0. Additionally, the third row should be x−4=0 instead of x+4=0.
So, the correct table should look like this:
| | Equation | Solution |
|-----|--------------|------------|
| Row 1 | (x+3)(x+4)=0 | - |
| Row 2 | x+3=0 | -3 |
| Row 3 | x-4=0 | 4 |
| Row 4 | x=3 | 3 |
| Row 5 | x=-4 | -4 |
Therefore, the correct answer is "No, x−3=0 in the second row should be x+3=0, and x+4=0 in the second row should be x−4=0."