Show how many solutions are in the solution set for the equation 3x2=21.
infinitely many two one zero
There is only one solution in the solution set for the equation 3x2=21, which is x=√(21/3) = √7.
To determine the number of solutions in the solution set for the equation 3x^2 = 21, we can solve for x.
Step 1: Divide both sides of the equation by 3.
3x^2 / 3 = 21 / 3
x^2 = 7
Step 2: Take the square root of both sides of the equation.
√(x^2) = √7
x = ±√7
So, we have two solutions for x: x = √7 and x = -√7.
Therefore, the number of solutions in the solution set for the equation 3x^2 = 21 is two.
To determine the number of solutions in the solution set for the equation 3x^2 = 21, we need to solve the equation and see how many solutions it has.
Step 1: Start with the given equation: 3x^2 = 21.
Step 2: Divide both sides of the equation by 3 to isolate x^2:
(3x^2)/3 = 21/3.
x^2 = 7.
Step 3: Take the square root of both sides of the equation to solve for x:
√(x^2) = √7.
Since we have a square root, we need to consider both the positive and negative solutions:
x = ±√7.
Therefore, there are two solutions in the solution set for the equation 3x^2 = 21.