Starting from 200 ft away, your friend skates toward you and then passes you. She skates at a constant speed of 20 ft/s. Her distance d from you in feet after t seconds is given by d 200-20t. At what times is she 20 ft from you?
To find at what times your friend is 20ft from you, we need to set up the equation:
d = 20
Substituting the given equation for d:
200 - 20t = 20
Solving for t:
-20t = -180
t = 9
Therefore, your friend is 20ft from you at t = 9 seconds.
To find the times at which she is 20 ft from you, we need to set up an equation and solve for t.
The given equation for the distance (d) between you and your friend is:
d = 200 - 20t
We want to find when d is equal to 20 ft. So we can write the equation as:
20 = 200 - 20t
To solve this equation for t, we need to isolate the variable t. Let's first move the terms around to get rid of the constant on the right side:
20t = 200 - 20
Next, let's simplify the right side of the equation:
20t = 180
Now, we can solve for t by dividing both sides of the equation by 20:
t = 180/20
Simplifying further, we get:
t = 9
So, your friend will be 20 ft away from you after 9 seconds.
To find the times when your friend is 20 ft from you, we need to set the distance equation equal to 20 ft and solve for t.
Given that her distance from you is given by the equation: d = 200 - 20t
We can set this equation equal to 20:
200 - 20t = 20
Let's solve for t:
200 - 20t = 20
Subtract 200 from both sides:
-20t = 20 - 200
Simplify:
-20t = -180
Now divide both sides by -20 to isolate t:
t = (-180)/(-20)
Simplify:
t = 9
So, your friend will be 20 ft from you after 9 seconds.