For the length between landmark B (5,3) and F(14,4). Round the answer to the nearest hundredth if necessary
To find the length between two points (x1, y1) and (x2, y2), we can use the distance formula:
Distance = √((x2-x1)^2 + (y2-y1)^2)
In this case, the coordinates of landmark B are (5, 3) as (x1, y1) and the coordinates of landmark F are (14, 4) as (x2, y2).
So, the distance is:
Distance = √((14-5)^2 + (4-3)^2)
Distance = √(9^2 + 1^2)
Distance = √(81 + 1)
Distance = √82
Distance ≈ 9.06 (rounded to the nearest hundredth)
Therefore, the length between landmark B and F is approximately 9.06 units.
To find the length between two points in a coordinate plane, we can use the distance formula:
Distance = sqrt((x2 - x1)^2 + (y2 - y1)^2)
In this case, the coordinates of the two points are B(5,3) and F(14,4). Let's plug these values into the formula:
Distance = sqrt((14 - 5)^2 + (4 - 3)^2)
Simplifying further:
Distance = sqrt((9)^2 + (1)^2)
Distance = sqrt(81 + 1)
Distance = sqrt(82)
Rounding the answer to the nearest hundredth, we get:
Distance ≈ 9.06
Therefore, the length between landmark B(5,3) and F(14,4) is approximately 9.06 units.
To find the length between two points, B (5,3) and F (14,4), you can use the distance formula:
Distance = sqrt((x2 - x1)^2 + (y2 - y1)^2)
Plugging in the values:
x1 = 5, y1 = 3
x2 = 14, y2 = 4
Distance = sqrt((14 - 5)^2 + (4 - 3)^2)
Distance = sqrt(9^2 + 1^2)
Distance = sqrt(81 + 1)
Distance = sqrt(82)
Therefore, the length between B (5,3) and F (14,4) is approximately 9.05 when rounded to the nearest hundredth.