Find the prime factorization of 720
The prime factorization of 720 can be found by dividing the number by prime numbers successively.
By dividing 720 by 2, we get 360.
By dividing 360 by 2 again, we get 180.
By dividing 180 by 2 again, we get 90.
By dividing 90 by 2 again, we get 45.
By dividing 45 by 3, we get 15.
By dividing 15 by 3 again, we get 5.
Since 5 is a prime number, we stop dividing.
Therefore, the prime factorization of 720 is 2^4 × 3^2 × 5.
To find the prime factorization of 720, we need to determine the prime numbers that divide 720 evenly.
1. First, divide the given number, 720, by the smallest prime number, which is 2. We find that 720 ÷ 2 = 360.
2. Now, we will continue dividing the result obtained (360) by 2 until we can no longer divide evenly. 360 ÷ 2 = 180.
3. Again, divide 180 by 2: 180 ÷ 2 = 90.
4. Keep dividing by 2 until we can no longer divide evenly: 90 ÷ 2 = 45.
5. Now, 45 is an odd number. We have exhausted all the possible factors of 2, so we move on to the next prime number, 3.
6. Divide 45 by 3: 45 ÷ 3 = 15.
7. The process continues: divide 15 by 3: 15 ÷ 3 = 5.
8. Finally, divide 5 by 5: 5 ÷ 5 = 1.
The prime factorization of 720 is the multiplication of the prime numbers used in this division process:
2 × 2 × 2 × 2 × 3 × 3 × 5 = 2^4 × 3^2 × 5 = 720.
Therefore, the prime factorization of 720 is 2^4 × 3^2 × 5.
To find the prime factorization of 720, we need to find the prime numbers that divide into it.
Step 1: Divide by 2
720 divided by 2 is 360.
Step 2: Divide by 2
360 divided by 2 is 180.
Step 3: Divide by 2
180 divided by 2 is 90.
Step 4: Divide by 2
90 divided by 2 is 45.
Step 5: Divide by 3
45 divided by 3 is 15.
Step 6: Divide by 3
15 divided by 3 is 5.
Step 7: Divide by 5
5 divided by 5 is 1.
Now, let's write down the prime factors we used: 2, 2, 2, 2, 3, 3, 5.
So, the prime factorization of 720 is 2 x 2 x 2 x 2 x 3 x 3 x 5, written as 2^4 x 3^2 x 5.