Teresa is maintaining a camp fire. She can keep the fire burning for 4 hours with 6 logs. She wants to know how many logs (y) she needs to keep the fire burning for 18 hours. She assumes all logs are the same.
How many logs does Teresa need to maintain the fire for 18 hours?
To maintain the fire for 4 hours, Teresa needs 6 logs.
To maintain the fire for 1 hour, Teresa needs 6 logs / 4 hours = 1.5 logs.
Therefore, to maintain the fire for 18 hours, Teresa needs 1.5 logs/hour * 18 hours = 27 logs. Answer: \boxed{27}.
To find out how many logs Teresa needs to maintain the fire for 18 hours, we can set up a proportion using the given information.
We know that Teresa can keep the fire burning for 4 hours with 6 logs. Let's represent this information using a ratio:
4 hours / 6 logs
Now, we can set up a proportion by comparing this ratio to the desired time of 18 hours:
4 hours / 6 logs = 18 hours / y logs
In this proportion, "y" represents the number of logs Teresa needs to keep the fire burning for 18 hours.
To solve this proportion, we can use cross-multiplication. Multiply the numerator of the first ratio by the denominator of the second ratio, and vice versa:
4 hours * y logs = 6 logs * 18 hours
Simplifying further:
4y = 6 * 18
4y = 108
Now, divide both sides of the equation by 4 to isolate "y":
y = 108 / 4
y = 27
Therefore, Teresa needs 27 logs to maintain the fire for 18 hours.
To find out how many logs Teresa needs to maintain the fire for 18 hours, we can set up a proportion using the given information.
Let's set up the proportion:
4 hours / 6 logs = 18 hours / y logs
To solve for y, we can cross multiply:
4 * y = 18 * 6
Now let's solve for y:
4y = 108
Divide both sides by 4:
y = 108 / 4
Simplifying:
y = 27
Teresa needs 27 logs to maintain the fire for 18 hours.