___ Cl2(g) + ___ AlI3(aq) → ___ I2(aq) + ___AlCl3
balance this equation
1 Cl2(g) + 2 AlI3(aq) → 3I2(aq) + 2 AlCl3
To balance the given chemical equation:
___ Cl2(g) + ___ AlI3(aq) → ___ I2(aq) + ___ AlCl3
we need to ensure that the number of atoms on both sides of the equation is equal.
Let's proceed step by step:
1. Count the number of chlorine (Cl) atoms on both sides of the equation.
On the left side, we have 2 Cl atoms (from Cl2) and on the right side, we have 2 Cl atoms (from AlCl3). Therefore, the chlorine atoms are already balanced.
2. Next, count the iodine (I) atoms.
On the left side, we have 3 I atoms (from AlI3) and on the right side, we have 1 I atom (from I2). So, we need to balance the I atoms.
3. To balance the iodine atoms, we need to have the same number on both sides. We can achieve this by placing a coefficient in front of I2 on the right side of the equation.
The balanced equation now becomes:
___ Cl2(g) + ___ AlI3(aq) → 1 I2(aq) + ___ AlCl3
4. Finally, count the aluminum (Al) atoms.
On the left side, we have 1 Al atom (from AlI3) and on the right side, we have 1 Al atom (from AlCl3). Therefore, the aluminum atoms are already balanced.
The balanced equation is:
1 Cl2(g) + 2 AlI3(aq) → 1 I2(aq) + 2 AlCl3
To balance the given chemical equation:
Cl2(g) + AlI3(aq) → I2(aq) + AlCl3
We will balance it step-by-step:
Step 1: Count the number of atoms of each element present on both sides of the equation.
On the left side:
Cl: 2
Al: 1
I: 3
On the right side:
I: 2
Al: 1
Cl: 3
Step 2: Balance the least abundant element first. In this case, Al is already balanced.
Step 3: Balance the next least abundant element. In this case, Iodine (I) is not balanced.
Step 4: To balance I, we need to have the same number of I atoms on both sides. In this case, we have 3 I atoms on the left side and only 2 I atoms on the right side.
Step 5: Multiply the coefficient of I2(aq) by 3 to balance the I atoms on both sides:
Cl2(g) + AlI3(aq) → 3I2(aq) + AlCl3
Step 6: After multiplying the coefficient of I2, we check if the other elements are balanced. In this case, Al and Cl are still balanced.
Step 7: The equation is now balanced, with the final coefficients:
1 Cl2(g) + 2 AlI3(aq) → 3 I2(aq) + 2 AlCl3