at Oym A cam $50 for 5 more A members at Oym B down the steel costs $40 for 3 months. You the two equations in the turme of to try and pure out which membership would be cheaper for a year What is thea of the cheaper membershatit pant
I'm sorry, but it seems like there might be a few errors or missing information in your question. Can you please provide more details or clarify the equations you are referring to?
To compare the cost of membership for a year at Oym A and Oym B, we need to calculate the total cost for each membership for 12 months.
Let's start with Oym A:
Cost for 1 member for 1 month = $50
Cost for 5 more A members for 1 month = $50 * 5 = $250
Total cost for 6 members for 1 month at Oym A = $50 + $250 = $300
To calculate the cost for 12 months, we multiply the monthly cost by 12:
Total cost for 6 members for 12 months at Oym A = $300 * 12 = $3600
Now let's calculate the cost at Oym B:
Cost for the steel for 1 month = $40
Cost for 3 months = $40 * 3 = $120
Total cost for 5 members for 3 months at Oym B = $120 * 5 = $600
To calculate the cost for 12 months, we need to adjust the cost for 3 months to 12 months:
Total cost for 5 members for 12 months at Oym B = ($120 / 3) * 12 * 5 = $240 * 5 = $1200
Comparing the total costs:
Total cost for 6 members for 12 months at Oym A = $3600
Total cost for 5 members for 12 months at Oym B = $1200
Hence, the cheaper membership option for a year would be at Oym B, which would cost $1200.
To determine which membership is cheaper for a year, let's break down the information given:
Membership at Oym A costs $50 for 5 more members.
Membership at Oym B includes a steel discount, which reduces the cost by $40 for 3 months.
Let's represent the cost of one membership at Oym A as "A" and the cost of one membership at Oym B as "B".
We need to find the values of A and B to determine which membership is cheaper.
For Oym A:
The cost of 5 more members would be 5A.
Thus, the total cost for one year at Oym A would be 12A since there are 12 months in a year.
For Oym B:
The cost per month before the steel discount would be B.
The cost with the steel discount applied would be B - (40/3) since the discount is $40 for 3 months.
Thus, the total cost for one year at Oym B would be 12(B - (40/3)).
Now, we can set up the equations to compare the costs:
12A = 12(B - (40/3))
Simplifying the equation:
12A = 12B - 480/3
12A = 12B - 160
Dividing the equation by 12:
A = B - (160/12)
A = B - 40/3
This equation shows the relationship between the costs of the two memberships.
To determine which membership is cheaper for a year, we need to compare the values of A and B. If A is less than B, then membership at Oym A is cheaper; otherwise, membership at Oym B is cheaper.
If you have the actual values of A and B, you can substitute them into the equation to find the cheaper membership.