7y=8x-14 y =6 prove x=7
To prove that x = 7, we can substitute the value of y into the first equation and solve for x:
7y = 8x - 14
Substituting y = 6:
7(6) = 8x - 14
42 = 8x - 14
Adding 14 to both sides:
42 + 14 = 8x
56 = 8x
Dividing both sides by 8:
x = 7
Therefore, x = 7 has been proven.
To prove that x equals 7 using the given equation 7y = 8x - 14 and y = 6, we can substitute the value of y into the equation and solve for x.
Given:
7y = 8x - 14 ...(1)
y = 6
Substitute y = 6 into equation (1):
7(6) = 8x - 14
Multiply 7 by 6:
42 = 8x - 14
Add 14 to both sides of the equation:
42 + 14 = 8x
Simplify:
56 = 8x
Divide both sides by 8 to isolate x:
56/8 = x
7 = x
Therefore, by substituting y = 6 into the given equation, we have proved that x equals 7.
To prove that x = 7, we need to substitute the value of y in the given equations and solve for x.
Given: 7y = 8x - 14
y = 6
Substituting y = 6 into the first equation:
7 * 6 = 8x - 14
42 = 8x - 14
Next, let's isolate the x term:
42 + 14 = 8x
56 = 8x
Finally, divide both sides by 8 to solve for x:
56 / 8 = x
7 = x
Therefore, we have proven that when y = 6, x = 7.