One molecule of Iodine (I2) and two molecules of sodium chloride (NaCl) combine in a reaction. How many atoms are in the products?
In the reaction between one molecule of iodine (I2) and two molecules of sodium chloride (NaCl), the products formed are two molecules of sodium iodide (NaI).
The molecular formula for sodium iodide is NaI, which means it consists of one sodium atom (Na) and one iodine atom (I).
Therefore, the number of atoms in the products is 1 atom of sodium (Na) and 1 atom of iodine (I).
So, there are a total of 2 atoms in the products.
To determine the number of atoms in the products, we need to calculate the number of atoms present in one molecule of iodine (I2) and two molecules of sodium chloride (NaCl), and then add them up.
The molecular formula for iodine (I2) indicates that there are two iodine atoms per molecule.
The molecular formula for sodium chloride (NaCl) tells us that there is one sodium atom and one chlorine atom per molecule. Since we have two molecules of NaCl, we multiply the number of atoms by 2.
Therefore, we can calculate the total number of atoms in the products as follows:
Total number of atoms = Number of iodine atoms + Number of sodium atoms + Number of chlorine atoms
Number of iodine atoms = 2 (because there are two iodine atoms in one molecule of I2)
Number of sodium atoms = 1 x 2 (because there is one sodium atom in one molecule of NaCl, and we have two molecules of NaCl)
Number of chlorine atoms = 1 x 2 (because there is one chlorine atom in one molecule of NaCl, and we have two molecules of NaCl)
Total number of atoms = 2 + (1 x 2) + (1 x 2)
Total number of atoms = 2 + 2 + 2
Total number of atoms = 6
Therefore, in the reaction where one molecule of I2 and two molecules of NaCl combine, the products contain a total of 6 atoms.
To determine the number of atoms in the products, we need to balance the chemical equation and calculate the total number of atoms present in the molecules.
First, let's write the balanced chemical equation for the reaction:
1 I2 + 2 NaCl → 2 NaI + 1 Cl2
In the equation, we can see that one molecule of Iodine (I2) combines with two molecules of sodium chloride (NaCl) to produce two molecules of sodium iodide (NaI) and one molecule of chlorine gas (Cl2).
Now, let's count the number of atoms in each molecule:
- I2: 2 atoms of iodine (I)
- NaCl: 1 atom of sodium (Na) and 1 atom of chlorine (Cl)
- NaI: 1 atom of sodium (Na) and 1 atom of iodine (I)
- Cl2: 2 atoms of chlorine (Cl)
From this, we can calculate the total number of atoms:
Iodine (I): 2 atoms (from I2) + 2 atoms (from NaI) = 4 atoms
Sodium (Na): 2 atoms (from NaCl) + 2 atoms (from NaI) = 4 atoms
Chlorine (Cl): 2 atoms (from NaCl) + 2 atoms (from Cl2) = 4 atoms
Therefore, in the products of the reaction, there are a total of 4 atoms of iodine, 4 atoms of sodium, and 4 atoms of chlorine.