The following is a recursive function:%0D%0A%0D%0Adef countdown(n):%0D%0A if n == 0:%0D%0A return %0D%0A else:%0D%0A countdown(n - 1) %0D%0Acountdown(5)%0D%0AIn 3-5 sentences, explain the algorithm.
The recursive function named "countdown" takes an integer n as its input. If n is equal to 0, the function simply returns, indicating the base case. Otherwise, it calls itself again with the argument n-1, effectively reducing the number by 1. This process continues until n eventually becomes 0, at which point the function returns in each recursive call and terminates. In this specific code snippet, the countdown function is initially called with the argument 5.
The provided algorithm is a recursive function called "countdown". It takes an input parameter, "n", which represents the number to count down from. At each level of recursion, the function checks if the value of "n" is equal to zero. If it is, the function returns and ends the recursion. Otherwise, it calls itself with the parameter "n-1" to continue counting down to zero. This process continues until the base case of reaching zero is reached, and then the function returns and recursion ends. In this specific case, the countdown function is called with an input of 5, which means it will count down from 5 to 0 recursively.
The given recursive function, countdown(n), takes an input parameter n.
If n is equal to 0, the function returns without doing anything else. Otherwise, it calls itself with the parameter n - 1 to recursively countdown to 0.
This process continues until n becomes 0, at which point the function terminates. In this specific case, the countdown(5) call would recursively call countdown(4), countdown(3), countdown(2), countdown(1), and finally countdown(0).