A student stands on a skateboard and pushes on a wall with a force of 87N [S]. The total mass of the
student and the skateboard is 58kg. Calculate the acceleration of the student.
To calculate the acceleration of the student, we can use Newton's second law of motion, which states that the acceleration of an object is proportional to the net force acting on it and inversely proportional to its mass.
The net force acting on the student can be calculated using the force applied by the student and the force of gravity acting on the student:
Net force = applied force - force of gravity
The force of gravity can be calculated using the mass of the student and the acceleration due to gravity (9.8 m/s^2):
Force of gravity = mass * acceleration due to gravity
Let's substitute the given values into these equations:
Force of gravity = 58 kg * 9.8 m/s^2 = 568.4 N
Net force = 87 N - 568.4 N = -481.4 N
Since the force applied by the student is opposing the force of gravity, the net force is negative.
Now, we can calculate the acceleration using Newton's second law of motion:
Acceleration = Net force / mass
Acceleration = -481.4 N / 58 kg ≈ -8.3 m/s^2
Therefore, the acceleration of the student is approximately -8.3 m/s^2. The negative sign indicates that the student is accelerating in the opposite direction of the applied force.
To calculate the acceleration of the student, we can use Newton's second law of motion, which states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass. The formula for Newton's second law is:
F = m * a
Where:
F is the net force acting on the object,
m is the mass of the object, and
a is the acceleration of the object.
In this case, the net force acting on the student is the force with which they push on the wall, which is 87N to the south. The mass of the student and skateboard combined is 58kg.
The force and the acceleration are in the same direction (south), so the acceleration will be positive.
To calculate the acceleration, rearrange the formula to solve for a:
a = F / m
Plug in the values into the formula:
a = 87N / 58kg
Now, divide the force (87N) by the mass (58kg):
a ≈ 1.50 m/s^2
Therefore, the acceleration of the student is approximately 1.50 m/s^2 to the south.
To calculate the acceleration of the student, we can use Newton's second law of motion, which states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass.
Step 1: Identify the net force acting on the student. In this case, the net force is the force exerted on the wall, which is 87N [S].
Step 2: Calculate the acceleration. We can use the equation F = ma, where F is the net force, m is the mass of the object, and a is the acceleration.
Given:
Net force (F) = 87 N [S]
Mass (m) = 58 kg
Substituting the given values into the equation, we get:
87 N = 58 kg * a
Step 3: Solve for acceleration (a):
Divide both sides of the equation by the mass (58 kg):
87 N / 58 kg = a
Calculating:
a = 1.5 m/s^2
Therefore, the acceleration of the student is 1.5 m/s^2.