A motor gives an output power of 200kilovolts and operates with efficiency of 80%,if the constant input voltage to the motor is 200volts,determine the direct current
To determine the direct current (DC) input of the motor, we need to use the formula for power:
Power = Voltage × Current
Since the given input voltage is 200 volts, we can rearrange the formula to solve for the current:
Current = Power / Voltage
To find the input current, we need to convert the output power from kilovolts (kW) to volts (V). There are 1000 volts in 1 kilovolt, so:
Output Power = 200 kilovolts = 200,000 volts
Now we can calculate the input current:
Input Current = (Output Power × Efficiency) / Input Voltage
Input Current = (200,000 V × 0.8) / 200 V
Input Current = 160,000 V / 200 V
Input Current = 800 Amperes (A)
Therefore, the direct current input to the motor is 800 Amperes.
To determine the direct current (DC), we need to first find the input power to the motor. We can use the formula for power:
Power = Voltage * Current
Since the input voltage is given as 200 volts, we need to find the input current. We can rearrange the formula to solve for current:
Current = Power / Voltage
The input power can be calculated using the efficiency of the motor. Efficiency is defined as:
Efficiency = Output Power / Input Power
Rearranging this formula, we can solve for the input power:
Input Power = Output Power / Efficiency
Input Power = 200 kilovolts / (80/100)
Input Power = 200 kilovolts / 0.8
Input Power = 250 kilovolts
Converting the input power to volts:
Input Power (volts) = 250 kilovolts * 1000 volts/kilovolt
Input Power (volts) = 250,000 volts
Now we can substitute the values into the current formula:
Current = Input Power / Voltage
Current = 250,000 volts / 200 volts
Current = 1250 amps
Therefore, the direct current (DC) flowing into the motor is 1250 amps.
To determine the direct current (DC) of the motor, we need to calculate the input power first.
Step 1: Calculate the input power (Pin) using the formula:
Pin = Pout / Efficiency
Where:
Pin = Input power
Pout = Output power
Efficiency = Efficiency of the motor (expressed as a decimal)
Given:
Pout = 200 kilovolts
Efficiency = 80% = 0.8 (as a decimal)
Substituting the values:
Pin = 200 kilovolts / 0.8
= 250 kilovolts
Step 2: Convert the input power to volts.
1 kilovolt (kV) = 1000 volts
Pin = 250 kilovolts x 1000
= 250,000 volts
Therefore, the direct current (DC) of the motor is 250,000 volts.