A moon is orbiting Mars, rp is the shortest distance between the moon and its planet and ra is the longest distance between the moon and its planet. What is a moon's orbital eccentricity if rp is equal to .983 and ra is 1016. (1 point) Responses .016 .016 .012 .012 2.01 2.01 .033
The formula to calculate eccentricity is given by:
eccentricity (e) = (ra - rp)/(ra + rp)
Substituting the values, we have:
e = (1016 - 0.983)/(1016 + 0.983)
e = 1015.017/1016.983
e ≈ 0.997
Therefore, the moon's orbital eccentricity is approximately 0.997.
To calculate the eccentricity of a moon's orbit, you can use the following formula:
Eccentricity (e) = (ra - rp) / (ra + rp)
Given that rp is equal to 0.983 and ra is equal to 1016, let's substitute these values into the formula to find the eccentricity:
Eccentricity (e) = (1016 - 0.983) / (1016 + 0.983)
= 1015.017 / 1016.983
= 0.996
Therefore, the moon's orbital eccentricity is approximately 0.996.
To find the moon's orbital eccentricity, we can use the formula:
Eccentricity (e) = (ra - rp) / (ra + rp)
Given that rp is 0.983 and ra is 1016, we can substitute these values into the formula:
Eccentricity (e) = (1016 - 0.983) / (1016 + 0.983)
Calculating this expression yields:
Eccentricity (e) = 1015.017 / 1016.983
Finally, dividing the numerator by the denominator:
Eccentricity (e) ≈ 0.996
Therefore, the moon's orbital eccentricity is approximately 0.996.