Anne has $28.90 more savings than Beatrice 3 5 of Beatrices savings is the same as 1 2 of Annes savings how much does Anne have in savings?
Let Beatrice's savings be x dollars.
Then Anne has x+28.90 dollars in savings.
(3/5)x=(1/2)(x+28.90)
Multiply through by 10 to eliminate fractions:
6x=5(x+28.90)
6x=5x+144.50
6x-5x=144.50
x=144.50
Anne has x+28.90=144.50+28.90=$173.40 in savings. Answer: \boxed{173.40}.
Let's analyze the given information step-by-step:
1. Let's assume Beatrice's savings as 'x' dollars.
2. According to the problem, Anne has $28.90 more savings than Beatrice.
So, Anne's savings would be 'x + $28.90' dollars.
3. It is also mentioned that 3/5 of Beatrice's savings is equal to 1/2 of Anne's savings.
Mathematically, (3/5) * x = (1/2) * (x + $28.90).
4. We can solve the above equation to find the value of 'x' (Beatrice's savings).
Multiplying both sides of the equation by 10 (to eliminate fractions):
6x = 5(x + $28.90).
6x = 5x + $144.50.
6x - 5x = $144.50.
x = $144.50.
Therefore, Beatrice has $144.50 in savings.
5. We can now determine Anne's savings using the given information.
Anne's savings = Beatrice's savings + $28.90.
Anne's savings = $144.50 + $28.90.
Anne's savings = $173.40.
Hence, Anne has $173.40 in savings.
To find out how much Anne has in savings, let's break down the information given in the problem.
Let's assume Beatrice's savings amount is B dollars.
According to the problem, Anne has $28.90 more savings than Beatrice. So, Anne's savings can be expressed as B + $28.90.
It is also mentioned that 3/5 of Beatrice's savings is the same as 1/2 of Anne's savings.
Let's calculate these amounts separately:
- 3/5 of Beatrice's savings = (3/5)B
- 1/2 of Anne's savings = (1/2)(B + $28.90)
According to the problem, these two amounts are equal, so we can set up an equation using these values:
(3/5)B = (1/2)(B + $28.90)
Now, we can solve the equation to find the value of B, which represents Beatrice's savings:
Multiply both sides of the equation by 10 to eliminate the fractions:
10 * (3/5)B = 10 * (1/2)(B + $28.90)
6B = 5(B + $28.90)
Distribute on the right-hand side:
6B = 5B + $144.50
Subtract 5B from both sides to isolate B:
6B - 5B = $144.50
B = $144.50
Now that we know the value of B, we can calculate Anne's savings by substituting this value into the expression B + $28.90:
Anne's savings = $144.50 + $28.90 = $173.40
Therefore, Anne has $173.40 in savings.