There are 300 particles in an airtight container. Which adjustment would increase the speed of the particles? (1 point) Responses increasing the mass of the particles increasing the mass of the particles keeping the pressure constant and increasing the temperature keeping the pressure constant and increasing the temperature keeping the volume constant and cooling the container keeping the volume constant and cooling the container keeping the temperature constant and increasing the volume of the container

Increasing the temperature of the particles would increase their speed.

To increase the speed of the particles in an airtight container, you can adjust the temperature while keeping the pressure constant. Therefore, the correct response is: keeping the pressure constant and increasing the temperature.

To determine which adjustment would increase the speed of the particles in an airtight container, let's analyze the relationship between temperature, pressure, volume, and particle speed.

The speed of gas particles is directly related to their temperature, as described by the kinetic theory of gases. Higher temperature means higher average kinetic energy, resulting in faster-moving particles.

Based on the given options, two adjustments involve changing the temperature: increasing the temperature and keeping the pressure constant, or keeping the volume constant and cooling the container.

If the pressure is kept constant while increasing the temperature, the speed of the particles will increase. This is because an increase in temperature causes the gas particles to gain more energy, resulting in higher speeds.

On the other hand, if the volume is kept constant and the container is cooled, the particles' speed will decrease. Cooling the container decreases the temperature, which reduces the average kinetic energy of the particles, leading to slower speeds.

Therefore, the adjustment that would increase the speed of the particles in an airtight container is keeping the pressure constant and increasing the temperature.