Teresa is maintaining a camp fire. She can keep the fire burning for 4 hours with 6 logs. She wants to know how many logs (y) she needs to keep the fire burning for 18 hours. She assumes all logs are the same.
How many logs does Teresa need to maintain the fire for 18 hours?
We can set up a proportion to find the number of logs needed:
4 hours/6 logs = 18 hours/y logs
Cross-multiplying, we get:
4y = 18 * 6
Simplifying the right side, we get:
4y = 108
Dividing both sides by 4, we find:
y = 27
Therefore, Teresa needs 27 logs to maintain the fire for 18 hours. Answer: \boxed{27}.
To find out how many logs Teresa needs to maintain the fire for 18 hours, we can set up a proportion based on the given information.
Let's assume that x is the number of logs Teresa needs for 18 hours.
We can set up the proportion as:
4 hours / 6 logs = 18 hours / x logs
To solve for x, we can cross multiply:
4 hours * x logs = 6 logs * 18 hours
4x = 108
To isolate x, we can divide both sides of the equation by 4:
x = 108 / 4
x = 27
Therefore, Teresa needs 27 logs to maintain the fire for 18 hours.
To determine the number of logs Teresa needs to maintain the fire for 18 hours, we can use a proportion.
Let's start by setting up the proportion:
Hours: Logs
4 : 6
Since Teresa wants to know how many logs she needs for 18 hours, we'll set up the proportion like this:
4 : 6 = 18 : y
To solve for the unknown variable y, we can cross-multiply and solve for y.
4 * y = 6 * 18
4y = 108
Next, divide both sides of the equation by 4 to isolate the variable y.
y = 108 / 4
y = 27
Therefore, Teresa needs 27 logs to maintain the fire for 18 hours.