For what value of a will 8×103 be 40 times larger than a×102 ?
Let's set up the equation.
We know that 8×10^3 is 40 times larger than a×10^2.
So we can write:
8×10^3 = 40(a×10^2)
Simplifying the equation, we get:
8×10^3 = 40a×10^2
Dividing both sides by 10^2, we get:
8×10 = 40a
Multiplying 8 by 10, we get:
80 = 40a
Dividing both sides by 40, we get:
a = 2
Therefore, when a=2, 8×10^3 is 40 times larger than a×10^2.
To find the value of "a" for which 8×10^3 is 40 times larger than a×10^2, we can set up the equation:
8×10^3 = 40(a×10^2)
First, simplify the equation on the right side by multiplying 40 with "a":
8×10^3 = 40a×10^2
Next, simplify the equation by multiplying the exponents:
8×10^3 = 40a×10^2
8×10^3 = 40a×10^2
To get rid of the common factor of 10^2 on both sides, divide both sides of the equation by 10^2:
(8×10^3) / (10^2) = (40a×10^2) / (10^2)
Simplifying further:
8×10^1 = 40a
80 = 40a
Finally, divide both sides of the equation by 40 to solve for "a":
80 / 40 = 40a / 40
2 = a
Therefore, the value of "a" for which 8×10^3 is 40 times larger than a×10^2 is a = 2.
To find the value of "a" that makes 8×10^3 40 times larger than a×10^2, we need to set up an equation and solve for "a".
Let's denote the value of "a" as x.
The equation can be written as:
8×10^3 = 40(a×10^2)
To solve this equation, we need to first simplify the right side by multiplying 40 by the quantity a×10^2:
8×10^3 = 40a×10^2
Applying the properties of exponents, we can simplify the equation further by multiplying the exponents:
8×10^3 = 40a×10^(2+2)
Now, simplify the right side:
8×10^3 = 40a×10^4
To eliminate the common factor of 10^3 on both sides of the equation, we can divide by 10^3:
8 = 40a×10^(4-3)
8 = 40a×10
Now, divide both sides of the equation by 40 and simplify:
8/40 = a×10
1/5 = a×10
Finally, divide both sides of the equation by 10 to solve for "a":
(1/5) ÷ 10 = a
1/50 = a
Therefore, the value of "a" that makes 8×10^3 40 times larger than a×10^2 is 1/50.