In which situation did the car achieve the greatest efficiency? (Assume the cars all have the same mass.)(1 point)
Responses
a car that traveled 70 kilometers on 5.0 liters of gas
a car that traveled 70 kilometers on 5.0 liters of gas
a car that traveled 90 kilometers on 6.0 liters of gas
a car that traveled 90 kilometers on 6.0 liters of gas
a car that traveled 80 kilometers on 5.0 liters of gas
a car that traveled 80 kilometers on 5.0 liters of gas
a car that traveled 50 kilometers on 4.0 liters of gas
Based on the given information, the car that achieved the greatest efficiency was the one that traveled 90 kilometers on 6.0 liters of gas.
To determine which car achieved the greatest efficiency, we can calculate the fuel efficiency of each car by dividing the distance traveled by the amount of gas consumed.
Car 1: 70 km / 5.0 L = 14 km/L
Car 2: 90 km / 6.0 L = 15 km/L
Car 3: 80 km / 5.0 L = 16 km/L
Car 4: 50 km / 4.0 L = 12.5 km/L
Looking at the results, we can see that car 3 achieved the greatest efficiency, traveling 80 kilometers on 5.0 liters of gas, or 16 km per liter.
To determine which situation had the greatest efficiency, we need to calculate the gas mileage (kilometers per liter) for each car and compare the values.
First, let's calculate the gas mileage for each car:
Gas mileage = Distance traveled (in kilometers) / Amount of gas used (in liters)
For car 1:
Gas mileage = 70 km / 5.0 L = 14 km/L
For car 2:
Gas mileage = 90 km / 6.0 L = 15 km/L
For car 3:
Gas mileage = 80 km / 5.0 L = 16 km/L
For car 4:
Gas mileage = 50 km / 4.0 L = 12.5 km/L
Now, let's compare the gas mileage values:
Car 1: 14 km/L
Car 2: 15 km/L
Car 3: 16 km/L
Car 4: 12.5 km/L
Based on the calculations, we can see that car 3, which traveled 80 kilometers on 5.0 liters of gas, achieved the greatest efficiency with a gas mileage of 16 km/L.