A water tank decreases by 10 gallons every 3 hours every day. What is the total change in the amount of water in the tank after 6 days?(1 point)
Responses
80 gallons
80 gallons
−80 gallons
negative 80 gallons
480 gallons
480 gallons
−480 gallons
The tank decreases by 10 gallons every 3 hours. There are 24 hours in a day, and 3 hours is one-eighth of a day. So, in a day, the tank decreases by 10*8 = <<10*8=80>>80 gallons.
After 6 days, the total change in the amount of water in the tank is 6*80 = <<6*80=480>>480 gallons.
The correct answer is 480 gallons.
To find the total change in the amount of water in the tank after 6 days, we need to calculate the change in gallons per day and then multiply it by the number of days.
The water tank decreases by 10 gallons every 3 hours, which means it decreases by 10 gallons/3 hours = 10/3 gallons per hour.
Since there are 24 hours in a day, the tank decreases by 10/3 gallons per hour * 24 hours = 80 gallons per day.
Therefore, the total change in the amount of water in the tank after 6 days is 80 gallons/day * 6 days = 480 gallons.
So the correct answer is: 480 gallons.
To find the total change in the amount of water in the tank after 6 days, we need to calculate the change per day and then multiply it by the number of days.
We know that the water tank decreases by 10 gallons every 3 hours. This means that it loses 10 gallons per (3/24) = 1/8 of a day.
So, the change in the amount of water per day is 10 gallons divided by 1/8 of a day, which is 10 * 8 = 80 gallons per day.
To find the total change in the amount of water after 6 days, we multiply the change per day (80 gallons) by the number of days (6).
Therefore, the total change in the amount of water in the tank after 6 days is 80 * 6 = 480 gallons.
So, the correct answer is 480 gallons.