which of the following equations demonstrates the law of conservation mass
a. CH4 + O2 -> CO2 + HO
B. CH4 + O2 -> CO2 + H2O
C CH + O2 -> CO2 + H2O
D CH4 + O2 -> C + 2H2O
The equation that demonstrates the law of conservation of mass is B. CH4 + O2 -> CO2 + H2O. This is because the number and types of atoms (carbon, hydrogen, and oxygen) on both sides of the equation are equal, indicating that mass is conserved in the reaction.
The equation that demonstrates the law of conservation of mass is:
B. CH4 + O2 -> CO2 + H2O
This equation shows that methane (CH4) and oxygen (O2) react to form carbon dioxide (CO2) and water (H2O). Notice that the number of atoms for each element is the same on both sides of the equation, thus demonstrating the law of conservation of mass.
To determine which equation demonstrates the law of conservation of mass, we need to check if the number of atoms of each element is the same on both sides of the equation. The law of conservation of mass states that matter cannot be created or destroyed in a chemical reaction, so the number of atoms of each element should remain constant.
Let's analyze each equation:
a. CH4 + O2 -> CO2 + HO
In this equation, the number of carbon (C) atoms on the left side is 1, while the number of carbon atoms on the right side is also 1. The number of hydrogen (H) atoms on the left side is 4, while the number of hydrogen atoms on the right side is 1. The number of oxygen (O) atoms on the left side is 2, while the number of oxygen atoms on the right side is also 2. This equation does not demonstrate the law of conservation of mass since the number of hydrogen atoms changes.
B. CH4 + O2 -> CO2 + H2O
In this equation, the number of carbon (C) atoms on the left side is 1, while the number of carbon atoms on the right side is also 1. The number of hydrogen (H) atoms on the left side is 4, while the number of hydrogen atoms on the right side is 2. The number of oxygen (O) atoms on the left side is 2, while the number of oxygen atoms on the right side is also 2. This equation demonstrates the law of conservation of mass since the number of atoms of each element is the same on both sides.
C. CH + O2 -> CO2 + H2O
In this equation, the number of carbon (C) atoms on the left side is 1, while the number of carbon atoms on the right side is also 1. The number of hydrogen (H) atoms on the left side is 1, while the number of hydrogen atoms on the right side is 2. The number of oxygen (O) atoms on the left side is 2, while the number of oxygen atoms on the right side is also 3. This equation does not demonstrate the law of conservation of mass since the number of hydrogen and oxygen atoms changes.
D. CH4 + O2 -> C + 2H2O
In this equation, the number of carbon (C) atoms on the left side is 1, while the number of carbon atoms on the right side is also 1. The number of hydrogen (H) atoms on the left side is 4, while the number of hydrogen atoms on the right side is 4. The number of oxygen (O) atoms on the left side is 2, while the number of oxygen atoms on the right side is 4. This equation does not demonstrate the law of conservation of mass since the number of oxygen atoms changes.
Therefore, the equation that demonstrates the law of conservation of mass is:
B. CH4 + O2 -> CO2 + H2O