How could you check to see if the point (5, 6) is the solution to the Linear System of equations?(1 point)
Responses
a Substitute 6 in for x and 5 in for y in both of the equations to see if both equations are true.
b Substitute 6 in for x and 5 in for y in one of the equations to see if the equation is true.
c Substitute 5 in for x and 6 in for y in one of the equations to see if the equation is true.
d Substitute 5 in for x and 6 in for y in both of the equations to see if both equations are true.
a Substitute 6 in for x and 5 in for y in both of the equations to see if both equations are true.
a Substitute 6 in for x and 5 in for y in both of the equations to see if both equations are true.
To check if the point (5, 6) is the solution to the linear system of equations, you can use option d - substitute 5 in for x and 6 in for y in both of the equations to see if both equations are true.
Here's how you would do it:
1. Take the first equation of the system and substitute x = 5 and y = 6 into the equation.
For example, if the first equation is 2x + 3y = 10, substitute x = 5 and y = 6:
2 * 5 + 3 * 6 = 10
Simplifying this equation, we get: 10 + 18 = 10
The result is 28 ≠ 10, so this equation is not true when (x, y) is (5, 6).
2. Now, take the second equation of the system and substitute x = 5 and y = 6 into the equation.
For example, if the second equation is 4x - 2y = 15, substitute x = 5 and y = 6:
4 * 5 - 2 * 6 = 15
Simplifying this equation, we get: 20 - 12 = 15
The result is 8 ≠ 15, so this equation is not true when (x, y) is (5, 6).
Since both of the equations are not true when (x, y) is (5, 6), we can conclude that the point (5, 6) is not the solution to the linear system of equations.