. The highest score on an Algebra test was 42 points more than the lowest. When add together, the lowest and highest score was 154. Find both the highest and lowest score
Let's assume that the lowest score is x.
According to the problem, the highest score is 42 points more than the lowest score, so it is x + 42.
We also know that the sum of the lowest and highest score is 154, which can be written as: x + (x + 42) = 154.
Simplifying the equation, we get: 2x + 42 = 154.
Subtracting 42 from both sides, we have: 2x = 112.
Dividing both sides by 2, we find: x = 56.
Therefore, the lowest score is 56, and the highest score is 56 + 42 = 98. Answer: \boxed{56, 98}.
Let's represent the lowest score as "L" and the highest score as "H".
According to the problem, the highest score was 42 points more than the lowest, so we can write an equation: H = L + 42.
The sum of the lowest and highest score is given as 154, so we can write another equation: L + H = 154.
Now, we can substitute the value of H from the first equation into the second equation.
L + (L + 42) = 154.
Combining like terms, we get: 2L + 42 = 154.
Next, we can solve for L by subtracting 42 from both sides of the equation:
2L + 42 - 42 = 154 - 42.
Simplifying further: 2L = 112.
Dividing both sides by 2: 2L / 2 = 112 / 2.
We find that L = 56.
We can substitute this value of L back into the first equation to find H:
H = L + 42 = 56 + 42 = 98.
Therefore, the lowest score is 56 and the highest score is 98.
To find the highest and lowest scores, we need to set up a system of equations based on the given information. Let's define the variable "x" as the lowest score on the test.
According to the problem, the highest score is 42 points more than the lowest score. So, the highest score can be expressed as "x + 42".
We know that when the lowest and highest scores are added together, the result is 154. So, we can write the equation:
x + (x + 42) = 154
Now we can solve this equation to find the value of x, which represents the lowest score:
2x + 42 = 154
Subtracting 42 from both sides to isolate the term with x:
2x = 112
Dividing both sides by 2 to solve for x:
x = 56
Therefore, the lowest score on the test is 56.
To find the highest score, we can substitute the value of x back into the equation:
highest score = x + 42 = 56 + 42 = 98
Hence, the highest score on the Algebra test is 98 and the lowest score is 56.