Use the table to answer the question. (x+3)(x+4)=0 x−3=0 x+4=0 x=3 x=−4While using the Zero Product Property to find the values of x that make the quadratic equation (x+3)(x+4) equals 0, Oliver completed the work provided in the table. Is Oliver’s work accurate?(1 point) Responses No, x−3=0 in the second row should be x+3=0. No, x minus 3 equals 0 in the second row should be x plus 3 equals 0 . No, x+4=0 in the second row should be x−4=0. No, x plus 4 equals 0 in the second row should be x minus 4 equals 0 . Yes, the work is accurate. Yes, the work is accurate. No, he should have a third column where he should set x=0. No, he should have a third column where he should set x equals 0 . Skip to navigation
No, x−3=0 in the second row should be x+3=0.
The correct response is: No, x−3=0 in the second row should be x+3=0.
No, Oliver's work is not accurate. In the second row of the table, x-3=0 should be x+3=0. Similarly, x+4=0 in the second row should be x-4=0. Therefore, the correct table should be:
(x+3)(x+4)=0 | x-3=0 | x+4=0
x=-3 or x=-4 | x=3 | x=-4
This shows that the values of x that make the quadratic equation (x+3)(x+4) equal to 0 are x=-3, x=-4, and x=3.