A shell is fired from a cliff that is 30 m above a horizontal plane. The muzzle speed of the shell is 75.0 m/s and it is fired at an elevation of 35° above the horizontal.
(a) Determine the horizontal range of the shell.
Initial Velocity = 75 m/s
Elevation angle = 35°
Height of the cliff = 30 m
Range = (initial velocity) ^2 * sin(2θ)/g
Range = (75 ^2 * sin (2*35°)) / 9.8 m/s
Range = (5625 * sin (70)) / 9.8 m/s
Range = 539.36 m
The horizontal range of the shell is approximately 539.36 m
(b) Determine the velocity of the shell as it strikes the ground.
Initial Velocity = 75 m/s
Elevation angle = 35°
Vertical Velocity = initial velocity * sin (θ)
Vertical velocity = 75 m/s * cos (35°)
Vertical Velocity = 61.44 m/s
The velocity of the shell is 61.44 m/s as it strikes the ground.
are these correct?