The senior class at Hartford High School is planning their prom. They’ve narrowed the location down to two choices. The Regal Hotel charges%2C C %2C %24500 for the ballroom rental fee and %2475 per student%2C s %2C for the meal. The Greenhill Country Club charges%2C C %2C %241%2C000 for the ballroom rental fee and %2465 per student%2C s %2C for the meal. Create a pair of linear equations that represent this real-world problem.(1 point) Responses Regal Hotel%3A C%3D1%2C000s%2B75%3B Greenhill Country Club%3A C%3D500s%2B65 Regal Hotel%3A upper C equals 1%2C000 s plus 75 %3B Greenhill Country Club%3A upper C equals 500 s plus 65 Regal Hotel%3A C%3D75s%2B500%3B Greenhill Country Club%3A C%3D65s%2B1%2C000 Regal Hotel%3A upper C equals 75 s plus 500 %3B Greenhill Country Club%3A upper C equals 65 s plus 1%2C000 Regal Hotel%3A C%3D500s%2B75%3B Greenhill Country Club%3A C%3D1%2C000s%2B65 Regal Hotel%3A upper C equals 500 s plus 75 %3B Greenhill Country Club%3A upper C equals 1%2C000 s plus 65 Regal Hotel%3A C%3D75s%2B1%2C000%3B Greenhill Country Club%3A C%3D65s%2B500
The correct pair of linear equations that represent this real-world problem is:
Regal Hotel: C = 500s + 75
Greenhill Country Club: C = 1000s + 65
The correct pair of linear equations that represent this problem is:
Regal Hotel: C = 500s + 75
Greenhill Country Club: C = 1000s + 65
The pair of linear equations that represent this real-world problem are:
1) Regal Hotel: C = 500s + 75
2) Greenhill Country Club: C = 1000s + 65
In these equations, C represents the total cost (in dollars) and s represents the number of students attending the prom. The equations show the relationship between the total cost and the number of students for each location option. By substituting different values for s into the equations, you can calculate the total cost for each location.