what's the distance between (3,8) and (7,12)
The distance between two points in a plane is given by the formula:
d = √( (x₂ - x₁)² + (y₂ - y₁)² )
Plugging in the coordinates, the distance between (3,8) and (7,12) is:
d = √( (7 - 3)² + (12 - 8)² )
= √( 4² + 4² )
= √( 16 + 16 )
= √32
≈ 5.66
Therefore, the distance between (3,8) and (7,12) is approximately 5.66 units.
To find the distance between two points in a coordinate plane, we can use the distance formula:
Distance = √((x2 - x1)^2 + (y2 - y1)^2)
Using the points (3,8) and (7,12):
Let (x1, y1) = (3,8)
Let (x2, y2) = (7,12)
Substituting the values:
Distance = √((7 - 3)^2 + (12 - 8)^2)
= √(4^2 + 4^2)
= √(16 + 16)
= √32
≈ 5.66
Therefore, the distance between the points (3,8) and (7,12) is approximately 5.66 units.
To find the distance between two points in a coordinate plane, we can use the distance formula. The distance formula gives the distance between two points (x1, y1) and (x2, y2) as follows:
d = √((x2 - x1)^2 + (y2 - y1)^2)
In this case, the two points are (3, 8) and (7, 12).
Using the formula, we can calculate the distance:
d = √((7 - 3)^2 + (12 - 8)^2)
= √(4^2 + 4^2)
= √(16 + 16)
= √32
= 5.656854249...
So, the distance between (3, 8) and (7, 12) is approximately 5.656854249 units.