David runs out of gas so he gets out of his car and walks 32 yards north and 85 blocks yards east. How far is he from his car if he walked back in a straight line? Round your answer to the nearest tenth david needs to walk about?

To find the distance David needs to walk back to his car, we can use the Pythagorean theorem, which states that in a right triangle, the square of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides.

Let's call the length of the distance David walked north "a" and the length of the distance he walked east "b". Using the Pythagorean theorem, we can find the distance David needs to walk back to his car, which is the hypotenuse of the right triangle formed by "a" and "b".

a = 32 yards
b = 85 yards

The distance David needs to walk back is given by the square root of (a^2 + b^2):

Distance = √(32^2 + 85^2)
Distance ≈ √(1024 + 7225)
Distance ≈ √8249
Distance ≈ 90.8 yards

Therefore, David needs to walk about 90.8 yards back to his car. Rounded to the nearest tenth, David needs to walk about 90.8 yards.

To find the distance David is from his car after walking back in a straight line, we can use the Pythagorean theorem.

The Pythagorean theorem states that in a right triangle, the square of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides.

In this case, the distance David walks north is 32 yards and the distance he walks east is 85 yards. We can consider these distances as the lengths of two sides of a right triangle, and the hypotenuse will represent the straight-line distance from his car.

Using the Pythagorean theorem, we can calculate the distance as follows:

Distance = √(32² + 85²)

Distance = √(1024 + 7225)

Distance = √8249

Distance ≈ 90.9 yards

Therefore, David needs to walk about 90.9 yards to get back to his car in a straight line.

To find the distance David needs to walk back to his car in a straight line, we can use the Pythagorean theorem.

The Pythagorean theorem states that for a right triangle, the sum of the squares of the two legs (the sides that are not the hypotenuse) is equal to the square of the hypotenuse (the side opposite the right angle).

In this case, the north walk and the east walk form the legs of the triangle, and the distance David needs to walk back to his car is the hypotenuse.

So, let's calculate:

Leg 1 (north walk) = 32 yards
Leg 2 (east walk) = 85 yards

Using the Pythagorean theorem:
Hypotenuse^2 = Leg 1^2 + Leg 2^2
Hypotenuse^2 = 32^2 + 85^2

Hypotenuse^2 = 1024 + 7225
Hypotenuse^2 = 8249

Now, we take the square root of both sides to find the length of the hypotenuse:
Hypotenuse = √8249

Calculating this value gives us approximately:
Hypotenuse ≈ 90.83 yards

Therefore, David needs to walk about 90.8 yards back to his car.