How many CO, molecules are produced when three glucose molecules undergo cellular respiration? (1 point)
• 12
3
6
• 18
The answer is 18.
To answer this question, we need to know the chemical equation for cellular respiration. The balanced equation for the complete oxidation of glucose is:
C6H12O6 + 6O2 → 6CO2 + 6H2O
From this equation, we can see that each glucose molecule is producing 6 molecules of carbon dioxide (CO2). Since we want to know the number of carbon monoxide (CO) molecules produced, we need to multiply the number of carbon dioxide molecules by 1.
Therefore, when three glucose molecules undergo cellular respiration:
3 glucose molecules × 6 CO2 molecules/glucose molecule = 18 CO2 molecules
Thus, 18 carbon dioxide (CO2) molecules are produced when three glucose molecules undergo cellular respiration.
To determine how many CO2 molecules are produced when three glucose molecules undergo cellular respiration, we need to understand the process of cellular respiration and the stoichiometry involved.
Cellular respiration is a metabolic process that occurs in the cells of living organisms, including humans. It involves the breakdown of glucose (a sugar molecule) to produce energy in the form of ATP. The general equation for cellular respiration is:
C6H12O6 + 6O2 → 6CO2 + 6H2O + energy (ATP)
From this equation, we can see that for every glucose molecule (C6H12O6) that undergoes cellular respiration, 6 CO2 molecules (carbon dioxide) are produced.
Since we are given three glucose molecules, we can calculate the total number of CO2 molecules produced by multiplying the number of glucose molecules by the stoichiometric coefficient for CO2.
3 glucose molecules x 6 CO2 molecules = 18 CO2 molecules
Therefore, the answer is 18 CO2 molecules.