Which of the following equations has the solution set {−3} ?
4x−8=−4 4 x minus 8 equals negative 4 4x+8=4 4 x plus 8 equals 4 4x−8=4 4 x minus 8 equals 4 4x+8=−4
The equation that has the solution set {-3} is 4x + 8 = -4.
To determine which equation has a solution set of {-3}, we need to substitute -3 for the variable x in each equation and check if the equation is true.
1. 4x - 8 = -4
Replacing x with -3, we get: 4(-3) - 8 = -4
Simplifying, we have: -12 - 8 = -4
-20 ≠ -4, so this equation does not have a solution of -3.
2. 4x + 8 = 4
Replacing x with -3, we get: 4(-3) + 8 = 4
Simplifying, we have: -12 + 8 = 4
-4 ≠ 4, so this equation does not have a solution of -3.
3. 4x - 8 = 4
Replacing x with -3, we get: 4(-3) - 8 = 4
Simplifying, we have: -12 - 8 = 4
-20 ≠ 4, so this equation does not have a solution of -3.
4. 4x + 8 = -4
Replacing x with -3, we get: 4(-3) + 8 = -4
Simplifying, we have: -12 + 8 = -4
-4 = -4, so this equation has a solution of -3.
Therefore, the equation that has the solution set {-3} is 4x + 8 = -4.
To determine which of the equations has the solution set {-3}, we need to substitute -3 into each equation and see which one satisfies the equation. Let's evaluate each equation using -3:
1. 4x - 8 = -4:
Substituting -3 for x, we get:
4(-3) - 8 = -4
-12 - 8 = -4
-20 ≠ -4
2. 4x + 8 = 4:
Substituting -3 for x, we get:
4(-3) + 8 = 4
-12 + 8 = 4
-4 ≠ 4
3. 4x - 8 = 4:
Substituting -3 for x, we get:
4(-3) - 8 = 4
-12 - 8 = 4
-20 ≠ 4
4. 4x + 8 = -4:
Substituting -3 for x, we get:
4(-3) + 8 = -4
-12 + 8 = -4
-4 = -4
After evaluating all the equations, we find that the equation "4x + 8 = -4" has the solution set {-3}.